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Musya8 [376]
3 years ago
12

What evidence did Darwin use to support his theory of evolution?

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:   Darwin spent five years on his journey as the ship's naturalist on the H.M.S. Beagle. Some of the evidence he used to support his theory was based on fossils he saw in South America. In the 1800's, most people were of the belief that the world was only a few thousand years old and that organisms that existed were unchanged since the beginning. However, the fossil evidence that he found showed giant versions of modern animals that no longer existed. It pointed to the idea of an ancestor that may have changed over time to the modern life forms that exist today. He also noted that the most likely place that the life forms on the Galapagos Islands could have come from originally, was Equador which was about 600 miles away. Differences in environment, food supply, temperature, etc. would put different pressures on animals on each of the various islands. Over time, natural selection would favor those best adapted for their various environments and after two million years, you have many different species that have evolved from common ancestors in Equador. The most famous of course, are Darwin's finches. Also famous are the different giant tortoises that vary by shells, size and habits, from island to island. Other famous animals include iguanas. One is extremely unique, the marine iguana, which is the only marine iguana in the entire world.

Explanation:

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Convert 19.2 moles to kL ??
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Answer:

30.8994048km

Explanation:

19.2 mi * 1.609344 km/1mi = 30.8994048 km

A common question isHow many mile in 19.2 kilometer?And the answer is 11.930326891 mi in 19.2 km. Likewise the question how many kilometer in 19.2 mile has the answer of 30.8994048 km in 19.2 mi.

8 0
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If you multiply 1/2 X 1/2 what will you get as you answer
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3 years ago
If 9.2 g of calcium react completely with excess aluminum chloride how many grams of aluminum would be produced?
Gekata [30.6K]

Explanation:

3Ca(s) + 2AlCl3(aq) -> 3CaCl2(aq) + 2Al(s)

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Therefore, we equate Ca to Aluminium which is the product whose mass we want to find

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". ". of Al- 27g/mol

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3×40 --> 2×27

9.2 --> x

x = 9.2×2×27= 496.8÷120=4.14

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