1 - 8
2 - 13
3 - 20
4 - 19
5 - 19
6 - 22
* protons - Atomic number
electrons - number of electrons is equal to number of protons k-41 is neutral
neutrons - Mass number - Atomic number
= 41 -19
= 22
Answer:
i = 2.483
Explanation:
The vapour pressure lowering formula is:
Pₐ = Xₐ×P⁰ₐ <em>(1)</em>
For electrolytes:
Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ
Where:
Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)
4.5701g of MgCl₂ are:
4.5701g ₓ (1mol / 95.211g) = 0.048000 moles
43.238g of water are:
43.238g ₓ (1mol / 18.015g) = 2.400 moles
Replacing in (1):
0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm
0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)
2.4mol + i*0.048mol = 2.4mol / 0.9527
2.4mol + i*0.048mol = 2.5192mol
i*0.048mol = 2.5192mol - 2.4mol
i = 0.1192mol / 0.048mol
<em>i = 2.483</em>
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I hope it helps!
1) Write the balanced chemical equation
4NH3 + 5O2 ----> 4NO + 6H2O
2) Write the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Write the proportions with the desired quantity of NO and the unknown quantity of O2
5 mol O2 / 4 mol NO = x / 18.0 mol NO
Solve for x: x = 18.0 mol NO * 5 mol O2 / 4 mol NO = 22.5 mol O2
4) Use the ideal gas equation to convert moles to volume
pV = nRT => V = nRT / p
n = 22.5 mol
R = 0.082 atm*liter / K * mol
T = 33 + 273.15 = 306.15 K
p = 874/760 atm = 1.15 atm
V = 22.5 mol * 0.082 atm*liter/K*mol * 306.15 K / 1.15 atm = 491.17 liter
Answer: 491 liters of O2
