Answer:
The correct answer is D. How gravity interacts with planets
Explanation:
Einstein's theory of relativity formulated in 1915 introduces the following concepts:
- Formula E = mc2 (relationship between energy, mass, speed of light)
- How nuclear energy is produced
-After seeing a solar eclipse, gravity is interpreted geometrically (which is an effect of distortion)
-Relative time
We have gravity here on earth while in space there’s none
Answer:
NO2- is the reducing agent.
Cr2O7_2- is the oxidizing agent.
H+ is neither
Explanation:
Reduction is the gain in electron. A chemical specie that undergoes reduction is called the oxidizing agent.
Oxidation is simply the loss in electrons. A chemical specie that undergoes oxidation is called the reducing agent.
Let us look at the species.
The first specie is the NO2-. In this specie, the oxidation number of nitrogen changed from +3 to +5 in NO3-. Thus we can see that there is more loss of electron to have caused an increase in the oxidation number positively. This shows an oxidation. Hence, NO2- is the reducing agent.
Let us look at the chromium. We can see that the oxidation number of chromium changed from +7 to +3.
Now we can see that it is a decrease and hence, it is a gain of electron and thus it is reduction. This means the first chromium specie is the oxidizing agent.
The hydrogen ion is simply placed there to balance the ions and hence it is neither the oxidizing nor the reducing agent.
Answer:
Answer is given below.
Explanation:
Anode is that electrode where oxidation occurs. Cathode is that electrode where reduction occurs.
In cell representation, half cell present left to salt-bridge notation
is anodic system and another half cell present right to salt-bridge notation is cathodic system.
So anode is Cu and cathode is Ag.
oxidation: 
[reduction: 
]
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chemical equation: 
Oxidizing agent is that species which takes electron from another species. Here 
takes electron from Cu. Hence is the oxidizing agent.
Reducing agent is that species which gives electron to another species. Here Cu gives electron to . Hence Cu is the reducing agent.
<h3>
Answer:</h3>
4.227 × 10^-19 Joules
<h3>
Explanation:</h3>
Energy of a photon of light is calculated by the formula;
E = hf, where h is the plank's constant, 6.626 × 10^-34 J-s and f is the frequency.
But, f = c/λ
Where, c is the speed of light (2.998 × 10⁸ m/s), and λ is the wavelength.
Given the wavelength is 470 nm or 4.7 × 10^-7 m
Therefore;
E = hc/λ
= (6.626 × 10^-34 J-s × 2.998 × 10^8 m/s) ÷ 4.7 × 10^-7 m
= 4.227 × 10^-19 Joules
Therefore, the energy of a photon with 470 nm is 4.227 × 10^-19 Joules
