Answer:
Wavelength of the first four spectral line:




Explanation:
Lman series when electron from higher shell number and jumps to 1st shell then all the possible lines is called as lyman series.
to calculate wavelength of first four spectral line:
For hydrogen Z=1;
by using rydberg equation
![\frac{1}{\lambda} =RZ^2[\frac{1}{n_1^2} -\frac{1}{n_2^2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3DRZ%5E2%5B%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20-%5Cfrac%7B1%7D%7Bn_2%5E2%7D%20%5D)
1. n=2 to n=1
![\frac{1}{\lambda} =RZ^2[\frac{1}{n_1^2} -\frac{1}{n_2^2} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Clambda%7D%20%3DRZ%5E2%5B%5Cfrac%7B1%7D%7Bn_1%5E2%7D%20-%5Cfrac%7B1%7D%7Bn_2%5E2%7D%20%5D)
=rydberg constant


2. n=3 to n=1


3. n=4 to n=1


4. n=5 to n=1


Answer:
(b) fully filled valence s orbitals
Explanation:
Electron configuration of Be: 1s22s2
2s2 is fully filled
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Answer:
2,760 grams NaCl
Explanation:
To find grams of NaCl, you need to (1) convert moles of Na to moles of NaCl (via mole-to-mole ratio from reaction) and (2) convert moles of NaCl to grams (via molar mass from periodic table). The final answer should have 3 significant figures based on the given measurement.
2 Na + Cl₂ --> 2 NaCl
Molar Mass (NaCl) = 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl) = 58.44 g/mol
47.2 moles Na 2 moles NaCl 58.44 grams
---------------------- x --------------------------- x ------------------------- =
2 moles Na 1 mole NaCl
= 2,758.368 grams NaCl
= 2,760 grams NaCl