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satela [25.4K]
3 years ago
8

How to find molarity 1.mass 2. molar mass 3. volume of water added?

Chemistry
1 answer:
anyanavicka [17]3 years ago
8 0

Molarity = (numer of mole solute) / (volume of the solution)

number of mole solute = mass solute/molar mass solute

Molarity =( mass solute/molar mass solute)/ (volume of the solution)=

= ( mass solute/((molar mass solute)*(volume of the solution))

If m is a mass of the solute, M is a molar mass a solute, V is a volume of the solution (we can think as a volume of water added).

Molarity = m/(M*V)

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What mass, in grams, of chlorine gas (Cl2) is contained in a 12.5-liter tank at 27.0 degrees Celsius and 2.85 atmospheres? Show
nata0808 [166]
PV = nRT
P is pressure, V is volume, n is number of moles, R is the gas constant, T is temperature in K

(2.85 atm)(12.5 L) = (n)(.08206)(27 C + 273)

n = 1.45 moles x 35.45 grams / mol Cl2 = 51.3 grams


8 0
3 years ago
Read 2 more answers
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
Assoli18 [71]

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

8 0
3 years ago
Hypothesis 2 (Particle size): If you ___ the particle size of a reactant, then the reaction rate will increase because ___ of th
vfiekz [6]

Answer: decrease / more

Explanation:

6 0
3 years ago
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Question:
guajiro [1.7K]

Answer:

What?

Explanation:

6 0
3 years ago
What is the molecular equation for the reaction of solid calcium carbonate with aqueous acetic acid.
malfutka [58]

Answer:

The molecular equation for the reaction of CaCO₃ with CH₃COOH is:

CaCO₃ (s) + 2CH₃COOH (aq) → Ca(CH₃COO)₂ (aq) + H₂O (l) + CO₂ (g)

Option 1

Explanation:

CaCO₃ + 2CH₃COOH → Ca(CH₃COO)₂ + H₂O + CO₂

Option 3 is the same equation as option 1, but calcium acetate, does not precipitate, so the formed salt, is not a solid.

Option 2 and 4 are wrong because calcium acetate molecular formula is

Ca(CH₃COO)₂

Ca(CH₃COO)₂  → Ca²⁺  +   2 CH₃COO⁻

5 0
3 years ago
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