The molarity of the solution made by dissolving 0.05 mole of HCl in 2 L of H₂O is 0.025 M
<h3>What is molarity? </h3>
Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the molarity </h3>
- Mole of HCl = 0.05 mole
- Volume = 2 L
- Molarity =?
Molarity = mole / Volume
Molarity = 0.05 / 2
Molarity = 0.025 M
Thus, the molarity of the solution is 0.025 M
Learn more about molarity:
brainly.com/question/9468209
One claim that supports one law of thermodynamics in photosynthesis is that energy is conserved, but the form of energy changes (Law 1).
<h3>What is photosynthesis?</h3>
Photosynthesis is a process done by plants and other organisms to obtain energy. This process implies a set of reactions that aim at converting light energy into chemical energy the organisms can use.
<h3>How is photosynthesis related to thermodynamics?</h3>
One way photosynthesis supports the laws of thermodynamics is through the first law that establishes energy is conserved, but the form of the energy can change.
This is because, in photosynthesis, the initial solar energy is transformed into chemical energy by storing the energy in carbon-hydrogen chemical bonds. This means the form of energy has changed but the energy is preserved.
Note: This question is incomplete because the graph is not given; due to this, I answered it based on general knowledge.
Learn more about photosynthesis in: brainly.com/question/1388366
Answer:
The temperature at 581.2 mL volume was 242.8 K.
Explanation:
Using Charle's law
Given ,
V₁ = 581.2 mL
V₂ = 830.5 mL
T₁ = ?
T₂ = 347 K
Using above equation as:
<u>The temperature at 581.2 mL volume was 242.8 K.</u>
Answer:
In a titration of 35.00 mL of 0.737 M H₂SO₄, 62.4 mL of a 0.827 M KOH solution is required for neutralization.
Explanation:
The balanced reaction is
H₂SO₄ + 2 KOH ⇒ 2 H₂O + K₂SO₄
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) 1 mole of H₂SO₄ is neutralized with 2 moles of KOH.
The molarity M being the number of moles of solute that are dissolved in a given volume, expressed as:

in units of 
then the number of moles can be calculated as:
number of moles= molarity* volume
You have acid H₂SO₄
- 35.00 mL= 0.035 L (being 1,000 mL= 1 L)
- Molarity= 0.737 M
Then:
number of moles= 0.737 M* 0.035 L
number of moles= 0.0258
So you must neutralize 0.0258 moles of H₂SO₄. Now you can apply the following rule of three: if by stoichiometry 1 mole of H₂SO₄ are neutralized with 2 moles of KOH, 0.0258 moles of H₂SO₄ are neutralized with how many moles of KOH?

moles of KOH= 0.0516
Then 0.0516 moles of KOH are needed. So you know:
- Molarity= 0.827 M
- number of moles= 0.0516
- volume=?
Replacing in the definition of molarity:

Solving:

volume=0.0624 L= 62.4 mL
<u><em>In a titration of 35.00 mL of 0.737 M H₂SO₄, 62.4 mL of a 0.827 M KOH solution is required for neutralization.</em></u>