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3 years ago

3p-2 greater than or equal to 1. What is the least possible value of 3p+2

Mathematics

1 answer:

Savatey [412]3 years ago

5 0

3p - 2 ≥ 1

3p ≥ 1 + 2

3p ≥ 3

p ≥ 3/3

p ≥ 1

This means that p is greater than 1 or equal to 1.

We now let p = 1 and plug into 3p + 2.

3(1) + 2

3 + 2

Answer: 5

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Annette [7]

6x-1=4x+6

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2 years ago

Given that x= -3, what is the value of 2×² - x + 5?

Roman55 [17]

Answer:

Step-by-step explanation:

2(9)-(-3)+5

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2 years ago

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If the passes through points (-4,-6) and ( 2 ,6), the rate of change of the line is equal to

Delvig [45]

Answer:

Step-by-step explanation:

Use rise over run (y2 - y1) / (x2 - x1)

Plug in the points:

(6 + 6) / (2 + 4)

12/6

= 2

So, the rate of change is 2

6 0

3 years ago

Write an equation where the left side is your power of 10 times n and the right side is the result of multiplying 0.1515... by t

Neko [114]

Answer:

$n10^x = 0.1515x$

Step-by-step explanation:

Required

Translate the statements to algebraic expression

Represent the power with x;

So, the left hand side is

Power of 10: $10^x$

Times n: $10^x * n$

The right hand side is:

0.1515 * power of 10: $0.1515 * x$

Equate the right hand side to the left:

$10^x * n = 0.1515 * x$

$n10^x = 0.1515x$

Hence;

The required expression is $n10^x = 0.1515x$

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2 years ago

What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

3 0

2 years ago