<h3>Answer: Approximately 191 bees</h3>
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Work Shown:
One way to express exponential form is to use
y = a*b^x
where 'a' is the initial value and 'b' is linked to the growth rate.
Since we're told 34 bees are there initially, we know a = 34.
Then after 4 days, we have 48 bees. So we can say,
y = a*b^x
y = 34*b^x
48 = 34*b^4
48/34 = b^4
24/17 = b^4
b^4 = 24/17
b = (24/17)^(1/4)
b = 1.090035
Which is approximate.
The function updates to
y = a*b^x
y = 34*(1.090035)^x
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As a way to check to see if we have the right function, plug in x = 0 and we find:
y = 34*(1.090035)^x
y = 34*(1.090035)^0
y = 34*(1)
y = 34
So there are 34 bees on day 0, ie the starting day.
Plug in x = 4
y = 34*(1.090035)^x
y = 34*(1.090035)^4
y = 34*1.4117629
y = 47.9999386
Due to rounding error we don't land on 48 exactly, but we can round to this value.
We see that after 4 days, there are 48 bees.
So we confirmed the correct exponential function.
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At this point we can find out how many bees there are expected to be after 20 days.
Plug in x = 20 to get
y = 34*(1.090035)^x
y = 34*(1.090035)^20
y = 190.672374978452
Round to the nearest whole number to get 191.
There are expected to be roughly 191 bees on day 20.
Answer:
$6018.15
Step-by-step explanation:
"is" number always goes on TOP "of" number.
"is" number is 79 1/2%
"of" number is $7570
<em>79 1</em><em>/</em><em>2</em><em> </em><em>%</em><em> </em><em>/</em><em> </em><em>$</em><em>7570</em><em> </em><em>*</em><em> </em><em>100</em><em> </em><em>=</em><em> </em><em>$</em><em>6018.15</em><em> </em>
<em>To</em><em> </em><em>find</em><em> </em><em>out</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>correct</em><em> </em><em>:</em>
<em>6018.15</em><em> </em><em>/</em><em> </em><em>7570</em><em> </em><em>*</em><em> </em><em>100</em><em> </em><em>=</em><em> </em><em>79.12</em><em>%</em>
Answer:
x < -6
Step-by-step explanation:
X/4 < -1.5
Multiply each side by 4
X/4*4 < -1.5*4
x < -6
There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960