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Papessa [141]
3 years ago
14

Please help 15 points

Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

infinitely many solutions

Step-by-step explanation:

Let's first eliminate y^2.  

To accomplish this, divide the 2nd equation by 5, obtaining

y^2 = 5/2 - x^2.  Now substitute this result for y in the first equation:


(-1/3)x^2 = -5/6 + (1/3)(5/2 - x^2), or

-x^2       -5         5        x^2

-------- = ------ + ------- -  --------    and this simplifies to:

    3         6          6         3

-x^2         x^2

------- = - -------    which is an identity and is thus always true.

  3             3

Thus, any value of x will satisfy this equation; there are infinitely many solutions.


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