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Amiraneli [1.4K]

3 years ago

15

I need help ASAP please

1 answer:

gulaghasi [49]3 years ago

4 0

Answer: x =168

Step-by-step explanation:I think it would be 80 plus 88 so its 168.

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Question 9 (5 points)

DochEvi [55]

Answer:

D

Step-by-step explanation:

8 0

3 years ago

Which sequence of transformations would maintain congruent ?

MakcuM [25]

218they are the annnns erv

7 0

3 years ago

My friend sets out walking at a speed of 3 miles per hour. I set out behind her 5 minutes later at 4 miles per hour.

MissTica

3 m/h=0.05m/m
.05•5=0.25 m/h I believe?

7 0

3 years ago

SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

2 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

r-ruslan [8.4K]

The first thing you should do is to determine all the zeros, and you will have 7, -11, 2 + 6i, 2 - 6i.
After that you have to <span>subtract and (x) from every each zero that you have above, which means
</span> $7-x, 

 -11-x, 

2 + 6i-x,

 2 - 6i-x
$
<span>And the last step is to multiply them together, and that's all you need!
</span> $(7-x)(-11-x)(2 + 6i-x)(2 - 6i-x)$
<span>I am pretty sure that everything hase become clear! Regards.</span>

6 0

3 years ago