Find the value of x. A. 53–√ m B. 241−−√ m C. 6 m D. 6+35–√ m
2 answers:
Answer:
<h2>x = 2√41 m</h2>
Step-by-step explanation:
Since the triangle is a right angled triangle we can use Pythagoras theorem to find the missing side x
Using Pythagoras theorem we have
a² = b² + c²
where a is the hypotenuse
From the question x is the hypotenuse
So we have
<h2>

</h2><h2 /><h2>

</h2><h2 /><h2>

</h2>
Find the square root of both sides
We have the final answer as
<h3>x = 2√41 m</h3>
Hope this helps you
Answer:
2 sqrt(41) =c
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
8^2 + 10^2 = c^2
64+ 100 = c^2
164 = c^2
take the square root of each side
sqrt(164) = sqrt(c^2)
sqrt(4*41) = c
2 sqrt(41) =c
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