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Murljashka [212]

3 years ago

5

When the scientist put in 50 ml of solution, the cell count was 205. When 40 ml of solution was used, the cell count was 200. Wh

ich equation models this data

1 answer:

notka56 [123]3 years ago

3 0

Answer:

every 10 mL of solution equals 5 cells

Step-by-step explanation:

I'm not sure if this equation is right but I think it's either 200÷40, 205÷50, or 205÷40 I hope this is kinda helpful.

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Maksim231197 [3]

Answer:

1,6,8

Step-by-step explanation:

8 0

3 years ago

An equilateral triangle has a side length of 12 centimeters. What is the measure, in centimeters, of its altitude?

STatiana [176]

Altitude forms a 30-60-90 (or 1-sqrt(3)-2) triangle. The hypotenuse is the equilateral triangle's side length, 12 centimeters. The altitude is the sqrt(3) side. 12 / sqrt(3) = 6sqrt(3). Therefore the altitude of the triangle is 6 * sqrt(3) centimeters.

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4 years ago

Which pack of fruit punch is the best buy? Explain.

stellarik [79]

Answer:

the 12 pack is the best deal

Step-by-step explanation:

2.95/4=0.7375=.74

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7 0

3 years ago

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mart [117]

The answer would be B

4 0

3 years ago

The Taylors plan to expand their

podryga [215]

Answer:

$A_{2} = 720\ ft^{2}$

Step-by-step explanation:

Let w and l be the width and length of the garage.

Let $A_{1}$ and $A_{2}$ be the area of garage at present and new garage.

Given:

The area of the garage at present

$A_{1}=80\ ft^{2}$

And he planed to tripling the dimensions of the garage.

We need to find the area of the new garage.

Solution:

We know the area of the rectangular garage.

$Area=width\times lendth$

$A_{1}=w\times l$

$w\times l=80$ ---------------(1)

The dimension of the new garage is triple, so the area of the new garage is.

$A_{2} = (3\times width)\times (3\times length)$

$A_{2} = (3\times w)\times (3\times l)$

$A_{2} = 9\times (w\times l)$

Substitute $w\times l=80$ from equation 1.

$A_{2} = 9\times (80)$

$A_{2} = 720\ ft^{2}$

Therefore, the area of the new garage $A_{2} = 720\ ft^{2}$

4 0

4 years ago