Answer: 16.5 gallons of water should be mixed to make a 20% solution of 
Step-by-step explanation: We are given the concentration of the solution in percentage, it can be taken as the molarity of the solution.
Now, to calculate the volume of water required, we use the formula:

where,
are the initial molarity and volume of the solution.
are the final molarity and volume of the solution.
Given:

Putting values in above equation, we get:

The number of people inside a mall is most of the time can't be counted using our fingers. The best way to describe the distribution of the hair colors at the mall is using B. MODE. Mode is measured as to how frequent an item (or a number) is repeated. By looking (bird's eye view) at the heads of the people, you can identify what hair color is dominant.
Answer:
The Standard Deviation
Step-by-step explanation:
Your concentration should be on what the standard deviation tells us about the data. The standard deviation is a number which measures how far the data are spread from the mean. Let a calculator or computer do the arithmetic. The standard deviation, s or σ , is either zero or larger than zero.
Put a thanks
Thank you
Answer:
a) 
b) 
And replacing we got:
![P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%205%29%20%3D%201-%5B0.01%2B0.02%2B0.03%2B0.12%2B0.11%5D%3D1-0.29%3D0.71)
Step-by-step explanation:
For this case we can solve this problem creating the following table
Number of particles Frequency Rel. Frequency
0 1 1/100 =0.01
1 2 2/100 =0.02
2 3 3/100=0.03
3 12 12/100=0.12
4 11 11/100=0.11
5 15 15/100=0.15
6 18 18/100=0.18
7 10 10/100=0.1
8 12 12/100=0.12
9 4 4/100=0.04
10 5 5/100=0.05
11 3 3/100=0.03
12 1 1/100=0.01
13 2 2/100=0.02
14 1 1/100=0.01
Total 100 1
We assume on this case the the relative frequency represent the probability.
Let X the number of contaminating particles on a silicon wafer
What proportion of the sampled wafers had at least one particle?
For this case we can use the complement rule like this:

At least five particles?
Again for this case we can use the complement rule and we got:

And replacing we got:
![P(X \geq 5) = 1-[0.01+0.02+0.03+0.12+0.11]=1-0.29=0.71](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%205%29%20%3D%201-%5B0.01%2B0.02%2B0.03%2B0.12%2B0.11%5D%3D1-0.29%3D0.71)