Five valence electrons for one nitrogen and 10 valence electrons for two nitrogens
The strength of an acid increases if the stability of conjugate base increases
The stability of a conjugate base increases with the presence of electron with drawing group (electronegative group)
Thus more the electronegativity of an atom attached to a carboxylic acid higher the strength of acid
In these examples CH3CH2CH2CF2CH2COOH contains to electronegative flourine atoms which stabilizes the conjugate base hence this will be the strongest acid among the given acids
Assuming that the reactants are:
(NH4)2SO4 (aq) + Ba(NO3)2 (aq)
and the products are:
BaSO4 (s) + 2NH4NO3 (aq),
then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.
According to the solubility rules, the following elements are considered insoluble when paired with SO4:
Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+
Therefore, the precipitate will be BaSO4 (s).
Answer:
negative
Explanation:
When something slows down, its acceleration is the opposite of the velocity.
The six metalloids are boron, silicon, germanium, arsenic, antimony, and tellerium.