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1 year ago

What volume of a 0. 100mhcl stock solution should be used to prepare 250. 00ml of 0. 0250mhcl?.

Chemistry

1 answer:

Alex_Xolod [135]1 year ago

3 0

62.5 mL is prepare .

What is molarity?

Molar concentration is a unit of measurement for the concentration of a chemical species, specifically a solute, in a solution, expressed as the amount of substance per unit volume of solution. The most often used unit for molarity in chemistry is the number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units.

Molarity of the stock solution as 0.100 M

Volume of the dilute solution as 250 mL

Molarity of dilute solution as 0.0250 M

We are required to calculate the Volume of the stalk solution.

Taking the volume and molarity of the stock solution to be V₁ and M₁ respectively, and volume and molarity of the dilute solution to be V₂ and M₂ respectively.

We are going to use the dilution formula;

According to the dilution formula, M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

= (0.025 M × 0.25 L) ÷ 0.100 M

= 0.0625 L

But, 1 L = 1000 mL

V₁ = 62.5 mL

Therefore, the volume of the stock solution is 62.5 mL

Learn more about molarity from given link

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2 years ago

Platinum crystallizes with the face-centered cubic unit cell. The radius of a platinum atom is 139 pm. Calculate the edge length

horrorfan [7]

Answer:

Length = 393pm, Density = 21.3 g/cm^3.

Explanation:

From the question above, we have the following parameters or data which is going to aid in solving the above Question.

=> The radius of a platinum atom = 139 pm.

Therefore, the length can be calculated by making use of the formula given below:

Length = 2 √( 2r) = 2 × √ (2 × 139 × 10^-12m ) = 393 × 10^-10 m = 393pm.

The density can be calculated by making use of the chemical formula given below:

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3 years ago

g Ammonium nitrate was the oxidizing agent used that damaged the New York World Trade Center in 1993 and the Federal Building in

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Answer: $51.3\times 10^3$ kJ

Explanation:

The thermochemical equation for decomposition of ammonium nitrate is:

$NH_4NO_3(s)\rightarrow N_2O(g)+2H_2O(g)$ $\Delta H=-82.1kJ$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass= 50.0 kg = $50.0\times 10^3g$ (1kg=1000g)

$\text{Number of moles of ammonium nitrate}=\frac{50.0\times 10^3g}{80g/mol}=0.625\times 10^3moles$

According to stoichiometry:

1 mole of $NH_4NO_3$ gives = 82.1 kJ of heat

Thus $0.625\times 10^3moles$ of $NH_4NO_3$ give = $\frac{82.1}{1}\times 0.625\times 10^3=51.3\times 10^3$ kJ of heat

Thus $51.3\times 10^3$ kJ of heat is evolved from the decomposition of 50.0 kg of ammonium nitrate.

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3 years ago

How to tell if an equation is acidic or basic?

Ilia_Sergeevich [38]

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