Answer: 1.2 M
Explanation:
Given that:
volume of NaCl = 392 mL
Convert volume in milliliters to liters
(since 1000 mL = 1L
392 mL = 392/10000 = 0.392 L)
Concentration of NaCl = ?
Amount of moles of NaCl = 0.47 moles
Recall that the concentration of a solution depends on the amount of solute dissolved in a particular volume of solvent.
I.e Concentration in mol/L =
Amount in moles / Volume in liters
= 0.47 moles / 0.392 L
= 1.199 mol/L (Round up to the nearest tenth as 1.2 M)
Note that molarity is the same as concentration in moles per litres.
Thus, the molarity of 392 mL of solution that contains 0.47 mol NaCl is 1.2 M
Explanation:
The given data is as follows.
= 98.70 kPa = 98700 Pa,
T =
= (30 + 273) K = 303 K
height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)
Density = 13.534 g/mL = 
= 13534 
The relation between pressure and atmospheric pressure is as follows.
P = 
Putting the given values into the above formula as follows.
P = 
= 
= 102683.05 Pa
= 102.68 kPa
thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.