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Butoxors [25]
3 years ago
7

Which item is made from an acidic ingredient? (

Chemistry
2 answers:
nika2105 [10]3 years ago
8 0

The correct answer is D) Vinegar. Since vinegar reacts to baking soda (which is basic), I know that, based on the question, vinegar is the correct answer.

german3 years ago
7 0

the answer is baking soda


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Chlorine (cl) has an atomic number of 17. it often forms an ion by gaining 1 electron. what would its charge be?
Aliun [14]

Answer:

= -1

Explanation:

  • Chlorine belongs to the halogen group in the periodic table. It has an atomic number of 17, which indicates the number of protons and electrons in a neutral atom of chlorine is 17.
  • Therefore; with an atomic number of 17, its electronic configuration will be 2:8:7.
  • Thus; to attain a stable configuration chlorine requires to gain one electron, by so doing it becomes a negatively charged ion with a charge of -1.
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3 years ago
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Light waves are ______ waves.
Vladimir [108]

Answer:

good

Explanation:

6 0
4 years ago
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H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.06×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.18×10−19, what is the equilibrium constant Kfinal for
serg [7]

Answer:

Therefore the equilibrium constant  K_{final} is 9.35× 10²⁵

Explanation:

Equilibrium constant:

Equilibrium constant is used to find out the ratio of the concentration of the product to that of reactant.

xA+yB→zC

The equilibrium constant K,

k=\frac{[C]^z}{[A]^x[B]^y}

Here [A] is equilibrium concentration of A

[B] is equilibrium concentration of B

[C] is equilibrium concentration of C.

1.  H_2S(aq)\rightleftharpoons HS^-(aq)+H^+(aq)          K_1= 9.06 \times 10^{-8}

K_1=\frac{[HS^-][H^+]}{[H_2S]}

2.   HS^-(aq)\rightleftharpoons S^{2-}(aq)+H^+(aq)      K_2= 1.18 \times 10^{-19}

K_2=\frac{[S^{2-}][H^+]}{[HS^-]}

3.

S^{2-}(aq)+2H^+(aq)\rightleftharpoons  H_2S(aq)

K_3=\frac{[H_2S]}{[S^{2-}][H^+]^2}

Therefore,

k_1k_2=\frac{[HS^-][H^+]}{[H_2S]}\frac{[S^{2-}][H^+]}{[HS^-]}

\Rightarrow k_1k_2=\frac{[S^{2-}][H^+]^2}{[H_2S]}

\Rightarrow k_1k_2=\frac{1}{K_3}

\Rightarrow K_3=\frac{1}{K_1K_2}

\Rightarrow K_3=\frac{1}{9.06\times 10^{-8}\times 1.18\times 10^{-19}}

⇒K₃=9.35× 10²⁵

K_3=K_{final}          

Therefore the equilibrium constant  K_{final} is 9.35× 10²⁵

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Hydrogen reacts with oxygen to produce water.
garik1379 [7]
If I were you I’d give more points for this hard of a question! If I were you I’d give more points for this hard of a question! If I were you I’d give more points for this hard of a question! Hahahhahsjsjndjfktntnfjd
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