Answer:
Please see the attached pictures.
Explanation:
☆ To ensure that each carbon has 4 bonds, fill the other bonds with Hs.
Percentage yield = (actual yield / theoretical
yield) x 100%<span>
The balanced equation for the reaction is,
CH₄(g) + Cl₂<span>(g) </span>→ CH₃Cl(g)
+ HCl(g)</span><span>
Since there is excess of Cl₂ gas, we can assume that all of CH₄ gas are reacted.</span><span>
Moles of CH₄(g) = mass / molar mass</span><span>
= 25.0 g / 16 g/mol
= 1.5625 mol
The stoichiometric ratio between CH₄(g) and CH₃Cl(g)
is 1 : 1</span><span>
Hence moles of CH₃Cl(g) = 1.5625 mol</span><span>
Molar mass of CH₃Cl(g) = 50.5 g/mol</span><span>
Mass of CH₃Cl(g) = number of moles x molar mass</span><span>
= 1.5625 mol x 50.5 g/mol
<span>
= 78.9 g</span>
Hence theoretical yield = 78.9 g
Actual yield = 45.0 g
Hence,
<span> Percentage yield = (45.0 g / 78.9 g) x 100% </span>
<span>
= 57.03%</span></span>
Answer: I think probaly wrong so probaly dont
listen to me
Explanation:
Answer:
Cl₂(g) + 2 KBr(aq) ⇒ Br₂(l) + 2 KCl(aq)
Explanation:
Let's consider the unbalanced single displacement reaction between chlorine and potassium bromide.
Cl₂(g) + KBr(aq) ⇒ Br₂(l) + KCl(aq)
We will start balancing Cl atoms by multiplying KCl by 2.
Cl₂(g) + KBr(aq) ⇒ Br₂(l) + 2 KCl(aq)
Finally, to get the balanced equation, we have to multiply KBr by 2.
Cl₂(g) + 2 KBr(aq) ⇒ Br₂(l) + 2 KCl(aq)
