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Papessa [141]
2 years ago
13

Are the following equivalent?

Mathematics
1 answer:
wlad13 [49]2 years ago
6 0

Answer:

yes

Step-by-step explanation:

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Plz help I’m bad at math
Advocard [28]

Answer:

1 is 136, 2 is 44, annd 4 is 44

Step-by-step explanation:

6 0
3 years ago
What is the mean of the values in the dot plot?
kari74 [83]

Answer:

Mean = 19.5

Step-by-step explanation:

Mean = sum of numbers ÷ Amount of numbers

Mean = \frac{16+17+17+17+17+19+19+19+19+21+22+22+23+25}{14}

Mean = \frac{273}{14}

Mean = 19.5

3 0
3 years ago
Pls help ASAP in a call with only my teacher
mixer [17]

Answer:

a

Step-by-step explanation:

the answer is a. 6 faces 12 edges and 8 vertices

4 0
3 years ago
Read 2 more answers
Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a
LekaFEV [45]
To make this a little clearer, let's give the pairs of inequalities the same denominator:

<span>Question 1: 
</span>\frac{11}{15} ? \frac{5}{7}
First, apply the common denominator to the first fraction:
(\frac{11}{15})7 \\  \frac{11}{15} *  \frac{7}{7}  \\  \frac{11*7}{15*7}  \\  \frac{77}{105}
Do the same for the second:15( \frac{5}{7}) \\  \frac{5}{7}* \frac{15}{15} \\  \frac{5*15}{7*15}  \\  \frac{75}{105}
Nest, compare the two fractions:
\frac{77}{105} \ \textgreater \   \frac{75}{105}
Therefore:
\frac{11}{15} > \frac{5}{7}
<span>
Question Two:</span>
\frac{5}{9} ? \frac{7}{13}
Apply the common denominator to fraction one:
13( \frac{5}{9}) \\  \frac{5}{9} * \frac{13}{13}  \\  \frac{5*13}{9*13}  \\  \frac{65}{117}
Fraction two:
9(\frac{7}{13}) \\  \frac{7}{13} *  \frac{9}{9}  \\  \frac{7*9}{13*9}  \\  \frac{63}{117}
Evaluate:
\frac{65}{117} > \frac{63}{117}
Therefore:
<span>\frac{5}{9} > \frac{7}{13}
</span>
Hope this helps!
5 0
3 years ago
Many companies use a quality control technique called acceptance sampling to monitor incoming shipments of parts, raw materials,
blondinia [14]

Answer:

A. 0.9510

B. 0.0480

C. 0.0490

D. No, I would not feel comfortable accepting the shipment if one item was found defective, because the probability is quite small to obtain 1 or more defective items.

8 0
3 years ago
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