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Papessa [141]
3 years ago
13

Are the following equivalent?

Mathematics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

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It is 3{:}32\text{ p.M.}3:32 p.M.3, colon, 32, start text, space, p, point, m, point, end text and Emma has gymnastics lessons a
Verizon [17]

Answer:

148 minutes

Step-by-step explanation:

It is 3{:}32\text{ p.M.}3:32 p.M.3, colon, 32, start text, space, p, point, m, point, end text and Emma has gymnastics lessons at 6{:}00\text{ p.M.}6:00 p.M.6, colon, 00, start text, space, p, point, m, point, end text How many minutes are there until Emma's gymnastics lessons?\

The time is 3:32 pm

Emma's gymnastics lesson is at 6:00 pm

6:00 pm - 3:32 pm = 2 hours 28 minutes

That is, we have 28 minutes before 4:00 pm

And 2 hours from 4:00 pm to 6:00 pm making a total of 2 hours 28 minutes

How many minutes are there until Emma's gymnastics lessons?

Convert 2 hours 28 minutes to minutes

1 hour = 60 minutes

2 hours = 60 minutes × 2 = 120 minutes

120 minutes + 28 minutes = 148 minutes

2 hours 28 minutes to minutes = 148 minutes

4 0
3 years ago
In the diagram below, AB is parallel to CD. What is the value of X?
Ivahew [28]
The answer would have to be 60
8 0
3 years ago
Read 2 more answers
Can u plz help me answer question 30
slamgirl [31]

We are given:

3x^3-2x^2

There seems to be nothing I can do to simplify this equation. However, I can factor out an x^2 since they both have at least an x^2. Here is what we get:

x^2(3x-2)

This is in the simplest form I can get into. I cannot do anything more to simplify this expression. This is your final answer.

3 0
3 years ago
Please help me figure out what x is
ivolga24 [154]

Answer:

the answer is 58 your welcome

8 0
2 years ago
The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t
velikii [3]

Answer:

3.84% of months would have a maximum temperature of 34 degrees or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.9, \sigma = 2.31

What percentage of months would have a maximum temperature of 34 degrees or higher?

This is 1 subtracted by the pvalue of Z when X = 34. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 29.9}{2.31}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

1 - 0.9616 = 0.0384

3.84% of months would have a maximum temperature of 34 degrees or higher

8 0
3 years ago
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