Question

Which is a possible equation of a parabola that intersects the x-axis at points (-1,0) and (3,0)? Question 2 options: y=x2+3x−3 y=x2−3x+2 y=x2−2x−3 y=x2+3x+2

Answer 1

Answer:

Step-by-step explanation:

Where a graph intersects the x-axis is where the solutions or zeros of the quadratic are found...where y = 0.

If the points of intersection are x = -1 and x = 3, then putting those into factors gives us (x + 1)(x - 3) = 0.  FOIL that out to get the quadratic.

$x^2-3x+x-3$ which simplifies to

$x^2-2x-3=y$

Looks like the third option there.