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Svetlanka [38]
4 years ago
5

In order to apply the law of sines to find the length of the side of a triangle, it is enough to know which of the following?

Mathematics
2 answers:
ch4aika [34]4 years ago
5 0

Answer:we must have two angles and a side so therefore, A IS THE CORRECT OPTION

Step-by-step explanation:

andrezito [222]4 years ago
5 0

Answer:

Two angles and a side

Step-by-step explanation:

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Help please its too hard
Varvara68 [4.7K]

Answer:

#6 = 1; #7 = A (5 gallons)

Step-by-step explanation:

#6 it is 1 because you are suppose to divide 10% of 50 which gave yuu $5 and then divide 5 by 20% which is 1

6 0
3 years ago
Which of the following statements are true? Select all that apply.
nlexa [21]
1. <span>true
example:
2+3=3+2
5=5

2. </span><span>true
</span>example:
3*4=4*3
12=12
<span>
3. false
</span>example:
6-3=3-6
3≠-3
<span>
4. </span><span>true
</span>example:
(4 + 3) + 2= 4 + (3 + 2)
7 + 2 = 4 + 5
9 = 9
<span>
5. false
</span>example:<span>
(9 - 6) - 3 = 9 - (6 - 3)
</span>3 - 3 = 9 - 3
0 ≠ 6

6. true
example:
<span>2(3+4)= 2*3+2*4
2 * 7 = 6 + 8
14 = 14</span>
6 0
3 years ago
Add or subtract (m^2-m+3)+(m-1)?
uysha [10]
First You would rewrite the equation:
M^2-m+3+m-1
Second: rewrite equation to Combine like terms
M^2-m+m+3-1
Answer:
M^2+2
4 0
3 years ago
Read 2 more answers
A frog is climbing out of a well that is 15 feet deep, the frog climbs 4 feet per hour, and then the frog slips back 1 foot whil
Mnenie [13.5K]

Answer:

10 hours

Step-by-step explanation:

Hello! :)

In 2 hours, he is going up 4 feet and down 1 which means he advances 3 feet every two hours.

15 ft/3 ft=5 ft

2 hours x 5 ft=10 more hours

Hope this could help!

7 0
4 years ago
Read 2 more answers
What is the​ long-run cost function if the production function is qequals=33Lplus+22​K? Let the cost of each unit of L be w and
user100 [1]

Answer:

C(q)equals=​(w/33​)q if ​(w/33​)greater than or equals≥​(r/22​), and ​(r/22​)q otherwise.

Step-by-step explanation:

The production function is q = 33L + 22​K

Cost function is then, C = wL+ rK

Minimising the functions, we get:

σ = wL+ rK+ λ(q -33L -22K)

dσ/dL = w - λ33 = 0 ----------(1)

dσ/dK = r - λ22 = 0 -----------(2)

dσ/dλ = q -33L -22K ---------(3)

From equation (1) and (2)

w/r ⇒ λ33 / λ22 ⇒ ³³/₂₂

Or, w = r(³³/₂₂)

Substitute for 'w' in C

C = r(³³/₂₂)L + rK

C = r [(³³/₂₂)L + K]

Or, (³³/₂₂)L + K = C / r

So, C/r = q    or    r = C/q

recall that w = r(³³/₂₂)

∴ w = (³³/₂₂)C/q

So, cost function C = wL+ rK

Substitute for 'w' and 'r' in the equation

4 0
4 years ago
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