Answer:
The final temperature of water is 56,7 ºC
Explanation:
We need to apply the specific heat capacity formula to solve this.
Q = m . C . ΔT
22,8 kJ = 150 g . 4,186 J/g °C . (Tfinal - 20,4º C)
(We need to convert kJ in J to use the specific heat of water, be careful with units)
22,8 kJ = 22800 J (x1000)
22800 J = 150 g . 4,186 J/g °C . (Tfinal - 20,4º C)
22800 J = 627,9 J/ºC (Tfinal - 20,4º C)
22800 J / 627,9 ºC/ J = (Tfinal - 20,4º C)
36,3ºC = Tfinal - 20,4º C
36,3ºC + 20,4º C = 56,7 ºC
