Answer:
https://www.usna.edu/Users/chemistry/morse/_files/documents/SC112-Chapter12/keyws12.2.doc
Explanation:
https://www.usna.edu/Users/chemistry/morse/_files/documents/SC112-Chapter12/keyws12.2.doc
work
Answer:
average atomic mass = 46.8509984 amu
Explanation:
To get the average atomic mass, we will follow these steps:
1- multiply the atomic mass of each isotope by its percentage of abundance
2- add the products
We are given that:
1- The first isotope has an atomic mass of 45.95293 and percentage of abundance equals 72%
2- The second isotope has an atomic mass of 47.94795 and percentage of abundance equals 11%
3- The third isotope has an atomic mass of 49.94479 and percentage of abundance equals 17%
Following the mentioned steps, we can get the average atomic mass as follows:
average atomic mass = (45.95293)(0.72)+(47.94795)(0.11)+(49.94479)(0.17)
= 46.8509984 amu
Hope this helps :)
Answer:
There is 117.4 kJ of heat absorbed
Explanation:
<u>Step 1: </u>Data given
Number of moles CS2 = 1 mol
Temperature = 25° = 273 +25 = 298 Kelvin
Heat absorbed = 89.7 kJ
It takes 27.7 kJ to vaporize 1 mol of the liquid
<u>Step 2:</u> Calculate the heat that is absorbed
C(s) + 2S(s) → CS2(l) ΔH = 89.7 kJ (positive since heat is absorbed)
CS2(l) → CS2(g) ΔH = 27.7 kJ (positive since heat is absorbed)
We should balance the equations, before summing, but since they are already balanced, we don't have to change anything.
C(s) + 2S(s)---> CS2 (g)
ΔH = 89.7 + 27.7 = 117.4 kJ
There is 117.4 kJ of heat absorbed
10. ¿Con qué soñaba la autora cuando era niña? ¿Qué espera hoy?
11. ¿Cómo describe ella su identidad? ¿Cómo se define?
12. ¿Por qué escribe Esmeralda Santiago? ¿Qué quiere expresar a sus lectores?
If enought heat was removed by water, its will probably evaporate or turn into steam.
