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aleksley [76]
3 years ago
8

Solve for x.

Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

Smaller x = 1/5

Larger x = 4

Step-by-step explanation:

Firstly,

(x-4) = 0

x-4 = 0

x = 4

Secondly,

-5x +1 = 0

-5x = -1

x= 1/5

Hope it helps!

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Can someone let me know if I simplified these equations correctly or at least show me how to do it?
Grace [21]

Answer:

  Your work is correct as far as it goes. Now eliminate the terms that are zero.

Step-by-step explanation:

Multiplying anything by zero gives zero. Adding zero is like adding nothing. Zero is called the "additive identity element" because ...

  a + 0 = a

Adding zero doesn't change anything. You can (and should) drop the zero if your goal is to simplify the expression.

a. \quad x_{f}=v_{0}\\\\b. \quad x_{f}=v_{0}t\\\\c. \quad v_{f}^2=v_{0}^2

8 0
3 years ago
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

8 0
3 years ago
Helppppppppppppppopo
Vesna [10]
The answer is A, all that was needed was to do the math.

8 0
3 years ago
Read 2 more answers
In ΔEFG, the measure of ∠G=90°, EF = 95 feet, and FG = 26 feet. Find the measure of ∠F to the nearest degree.
Firdavs [7]

Answer:

74.4°

Step-by-step explanation:

Given

  • ∠G=90° => ΔEFG is a right triangle
  • EF = 95 feet
  • FG = 26 feet

Use sine law to find ∠F

As we know:

Sin(GEF)/ GF = Sin(EGF)/EF

<=> Sin(GEF) / 26 = Sin(90)/95

<=>Sin(GEF) / 26 = 1/95

<=> Sin(GEF)  = 26/95

<=> ∠GEF ≈ 15.8°

=> ∠F = 180° - ∠G - ∠GEF

∠F = 180° - 90° - 15.8° = 74.4°

3 0
3 years ago
Read 2 more answers
57.4 divided by 10???????
Gnesinka [82]
57.4/10=5.74
the answer is 5.74

6 0
3 years ago
Read 2 more answers
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