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laiz [17]
3 years ago
11

Is #25 balanced correctly? If not please help

Chemistry
2 answers:
Afina-wow [57]3 years ago
3 0
Yes it is correctly balanced. :) 
dezoksy [38]3 years ago
3 0
It is already correct balanced equation!
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write the balanced molecular chemical equation for the reaction in aqueous solution for sodium hydroxide and tin(iv) acetate. if
dimaraw [331]

The reaction of Sodium hydroxide and Tin(iv) acetate is as follows:

Sodium Hydroxide + Tin(IV) Acetate = Sodium Acetate + Tin(IV) Hydroxide

NaOH + Sn(C2H3O2)4 = C2H3NaO2 + Sn(OH)4

<u>Balanced Chemical Equation</u>:

4NaOH + Sn(C2H3O2)4 → 4C2H3NaO2 + Sn(OH)4

What is an Aqueous solution?

An aqueous solution is one in which water serves as the solvent. It is also known as a water-based solution. Many common chemical substances are dissolved in water, and these are called aqueous solutions. Examples of aqueous solutions include saltwater, vinegar, and sugar water.

What is Sodium hydroxide?

Sodium hydroxide, also known as lye or caustic soda, is a white, solid crystalline substance used in a number of industrial and household applications. It is a strong base that is highly soluble in water and can be used to adjust the pH of a solution. It is also used in the manufacture of soaps, detergents, and cleaning products.

What is Tin(IV)?

Tin(IV) is the chemical name for tin, which is a chemical element with the atomic number of 50. It is a silvery-white, malleable metal that is used in a variety of applications, including alloys, solders, and some electronics.

To know more about Sodium hydroxide,

LINK- brainly.com/question/29509565

CODE- #SPJ4

5 0
1 year ago
What do waves carry from place to place​
mario62 [17]

Answer:

Waves carry energy from place to place.

Explanation:

Some waves are used for mainly communication and phone signals. They help people get internet in the middle of nowhere if you are near an energy wave.

3 0
3 years ago
What is the molarity of a 1.44 (m/v)% solution of an HCOOOH (Formic acid)?
AlexFokin [52]

This problem is providing the mass-volume percent of a formic acid solution so its molarity is required and found to be 0.313 M after the following calculations.

<h3>Molarity</h3>

In chemistry, units of concentration provide a measurable understanding of the relationship between the relative amounts of both solute and solvent. In the case of molarity, one must relate moles of solute and liters of solution as follows:

M=\frac{mol\ solute}{Volume\ solution \ in \ L}

In such a way, when given this mass-volume percent of 1.44% for the formic acid in the solution, one can assume there is 100 mL of solution and 1.44 g of solute (formic acid), which means one must convert the volume to liters and the mass to moles with:

mol\ solute=\frac{1.44g}{46.03g/mol} =0.0313mol\\\\Volume\ in \liters: 100mL*\frac{1L}{1000mL}=0.100L

Finally, we plug in these numbers in the equation for the calculation of molarity:

M=\frac{0.0313mol}{0.100L}\\\\M=0.313M

Learn more about molarity: brainly.com/question/10053901

8 0
2 years ago
A student has a mass of 90 kg what would his weight be on mars if the acceleration due to gravity is 3.7 ?
Mumz [18]

Answer:

333N

Explanation:

Once we have the object's mass, we can find the weight by multiplying it by the gravitational force, which it is subject to. Being that Mars has a gravitational force of 3.7m/s2, we multiply the object's mass by this quantity to calculate an object's weight on mars.

So an object or person on Mars would weigh 37.83% its weight on earth. Therefore, a person would be much lighter on mars. Conversely, a person is 62.17% heavier on earth than on Mars.

3 0
3 years ago
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
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