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Rama09 [41]
3 years ago
10

A chemist prepares a solution of barium chlorate by measuring out of barium chlorate into a volumetric flask and filling the fla

sk to the mark with water. Calculate the concentration in of the chemist's barium chlorate solution. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Elan Coil [88]3 years ago
6 0

Complete Question

A chemist prepares a solution of barium chlorate BaClO32 by measuring out 42.g of barium chlorate into a 500.mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in /molL of the chemist's barium chlorate solution. Be sure your answer has the correct number of significant digits.

Answer:

The concentration is C =  0.28 \ mol/L

Explanation:

   From the question we told that

     The mass of Ba(ClO_{3})_2 is  m_b  =  42 \ g

     The volume of the solution  V_s  =  500 mL =  500*10^{-3} L

Now the number f moles of  Ba(ClO_{3})_2 in the solution is mathematically represented as

        n  =  \frac{m_b}{Z_b}

Where  Z_b is the molar mass of Ba(ClO_{3})_2 which a constant with a value

             Z_b  =  304.23 \ g/mol

Thus

       n = \frac{42}{304.23}

      n = 0.14 \ mol

The concentration of Ba(ClO_{3})_2  in the solution is mathematically evaluated as

       C =  \frac{n}{V_2}

substituting  values  

      C =  \frac{0.14}{500*10^{-3}}

      C =  0.28 \ mol/L

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