Answer : The correct answer for ions present in KCl is K⁺ and Cl⁻ which forms KCl by ionic bond (complete transfer of electron from K to Cl ) .
The electron dot structure : It is representation of valence electrons around the symbol of atoms.
Potassium : As it belongs to s -block , the electronic configuration of potassium is 1s² 2s² 2p⁶ 3s² 3p⁶4s¹ .Since Potassium has 1 electron in its outermost shell , so its electron dot structure involves K with one dot .
Chlorine : Chlorine belongs to p-block so the electronic configuration of Cl is 1s² 2s² 2p⁶ 3s² 3p⁵ . The valence electrons present in Cl is 7 , so the electron dot structure of Cl involves 7 dots around Cl .
The electron dot structures are shown in image.
Potassium chloride : It is ionic compound and formed by ionic bond between two ions , cations and anion . Cation is potassium and anion is chlorine.
Potassium being a metal , have tendency to donate the electron and form a cation . Since the outer shell has only 1 electron in it , so K easily loose this electron to gain stable configuration and form K⁺ ion .
Chlorine is a non metal and electronegative element ,so it has tendency to accept electron. and form anions. The electronic configuration of Cl is 1s² 2s² 2p⁶ 3s² 3p⁵ , that is , it is one electron short to complete the octet . Hence , it easily accepts one electron and form anion Cl⁻.
Potassium give its electron to Cl and forms ionic bond between K⁺ ion and Cl⁻ ion by complete transfer of one electron to form potassium chloride .(shown in image )