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spayn [35]
2 years ago
10

Density (D) is defined as the ratio of mass (m) to volume (V) and can be determined from the expression D = . Find the density o

f a sample of pure aluminum if a rectangular prism of volume 32.32 cm3 occupies a mass of 87.329 g. (Remember to put a space between your numerical value and the unit.)
Chemistry
1 answer:
olchik [2.2K]2 years ago
4 0

Explanation:

87.329 g/32.32 cm³ = 2. 70 g/cm³

You might be interested in
How many moles of iron would be needed to react with 3.82 moles of<br> oxygen
Rashid [163]

Answer:

5.09

Explanation:

8 0
3 years ago
How many grams are in 11.9 moles of chromirum
faust18 [17]

Answer:

Explanation:

Method 1 proportion

1 mole of chromium is 52 grams

11.9 moles = x grams

1/11.9 = 52/x                    Cross multiply

x = 11.9 * 52

x = 618.8                         grams

Now I have used an approximate mass for Chromium. The answer you get here is expected to reflect the weigth given on your periodic table Use that to get your answer. You should give a number very close to mine. Round to 3 places as in 619.

Method Two  Formula

mols = given mass / molecular mass

11.9 = given mass /  51.9961          Multiply both sides by  51.9961

11.9 *51.9961  = given mass            

given mass = 618.75

given mass = 619

3 0
3 years ago
A 200. gram sample of a salt solution contains 0.050 grams of NaCl. What is the concentration of the
wariber [46]

Answer:

2.5 × 10² ppm

Explanation:

Step 1: Given data

  • Mass of NaCl: 0.050 g
  • Mass of the sample: 200. g

Step 2: Convert 0.050 g to μg

We will use the conversion factor 1 g = 10⁶ μg.

0.050 g × 10⁶ μg/1 g = 5.0 × 10⁴ μg

Step 3: Calculate the concentration of NaCl in ppm

The concentration of NaCl in ppm is equal to the micrograms of NaCl per gram of the sample.

5.0 × 10⁴ μg NaCl/200. g = 2.5 × 10² ppm

3 0
3 years ago
Complete combustion of a 17.12mg sample of xylene In oxygen yielded 56.77mg
Veronika [31]

Xylene moles =\frac{17.12}{106.16×1000}=0.00016moles=

106.16×1000

17.12

=0.00016moles

Moles of CO_2 =\frac{56.77}{44.01×1000}=0.0013CO

2

=

44.01×1000

56.77

=0.0013

Moles of H_2O= =\frac{14.53}{18.02×1000}=0.0008H

2

O==

18.02×1000

14.53

=0.0008

Moles ratios

\frac{0.0013}{0.0008}=1.625

0.0008

0.0013

=1.625

\frac{0.0008}{0.0008}=1

0.0008

0.0008

=1

Hence molecular fomula

The empirical formula is C 4H 5.

The molecular formula C8H10

8 0
2 years ago
All organic molecules contain carbon and hydrogen. what parts of an organic molecule may contain oxygen, nitrogen, or phosphorus
Minchanka [31]
Answer is: <span>functional groups.
</span>Functional groups<span> are specific </span>groups<span> that are responsible for the characteristic chemical properties of molecule.</span>
<span>Proteins have nitrogen and oxygen in functional group.
Nucleic acids and some lipids have phosphorus in fuctional group.
Carbohydrates have oxygen in functional group for example.</span>
7 0
3 years ago
Read 2 more answers
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