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<h3>Answer:</h3>
6.26 g C
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right<u> </u>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
[Given] 3.14 × 10²³ atoms C
[Solve] grams C
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of C - 12.01 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
6.26227 g C ≈ 6.26 g C
Answer:
Here's what I get.
Explanation:
Your unbalanced nuclear equation is:
The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.
Then
95 = x + 2, so x = 95 - 2 = 93
243 = y + 4, so y = 243 - 4 = 239
Element 93 is neptunium, so the nuclear equation becomes