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3 years ago

What is this element 1s22s22p6?

Chemistry

1 answer:

butalik [34]3 years ago

6 0

If you add them up: 2+2+6 = 10, you will know it's Neon, which is written as Ne

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Kryger [21]

I can’t see the picture its too small

6 0

2 years ago

Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c

steposvetlana [31]

Answer:

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

Explanation:

$2CuO+C\rightarrow 2Cu+CO_2$

1 Ton = 907185 grams

Mass of copper oxide = 1.0 Ton = 907185 grams

Moles of copper oxide = $\frac{907185 g}{79.55 g/mol}=11,403.95 moles$

According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.

Then 11403.95 moles of copper oxide will react with:

$\frac{1}{2}\times 11403.95 mol=5,701.98 mol$ of carbon

Mass of 5,701.98 moles of carbon:

$5,701.98 mol\times 12 g/mol=68,423.75 g$

Mass of coke = x

Mass of carbon = 68,423.75 g

Percentage of carbon in coke = 95%

$95\%=\frac{68,423.75 g}{x}\times 100$

$x=720,250.09 g=0.794 Ton$

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

3 0

2 years ago

Base your answer to this question on the information below.During a bread-making process, glucose is converted to ethanol and ca

Damm [24]

Answer: 1 C6H12O6===> 2 C2H5OH + 2 CO2

75 In the space in your answer booklet, draw a structural formula for the alcohol formed in this reaction. [1]

Explanation:

6 0

2 years ago

Which change would increase the pressure exerted by a gas?

Gelneren [198K]

Answer:

C - raising the temperature of a gas

Explanation:

as you raise temperature, kinetic energy rises, and so does pressure

7 0

2 years ago

Which is the limiting reactant if we start with 30.0 g Al and 30.0 h O2

lorasvet [3.4K]

Explanation:

The limiting reactant will be Al:

4Al + 3O₂ → 2Al₂O₃

The limiting reactant is the reactant in short supply in a chemical reaction.

Given parameters:

Mass of Al = 30g Molar mass = 27g/mol

Number of moles = $\frac{mass}{molar mass}$ = $\frac{30}{27}$

Number of moles of Al = 1.111 mole

Mass of O₂ = 30g, molar mass = 32g/mol

Number of moles = $\frac{30}{32}$ = 0.94mol

In the reaction:

4 moles of Al reacted with 3 moles of O₂

1.11moles of Al will require $\frac{1.11 x3}{4}$ = 0.83mole to react

But we have been given 0.94mole of O₂. This is more than required.

Therefore O₂ is in excess and Al is the limiting reactant.

Learn more:

Limiting reagents brainly.com/question/6078553

#learnwithBrainly

4 0

2 years ago