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3 years ago

I need help on my math homework

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

7 0

Answer: the first one is True and the second one is false

Step-by-step explanation:

3 + 5x = 23

so replace x with 4 you get 3 + 5 * 4 = 3 + 20 = 23

this is equal to 23 so it is true

2x - 6 = 9

do the same you get

2 * 8 - 6 = 9

16 - 6 = 10

the answer is 10 not nine therefore it is false

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Answer:

Step-by-step explanation:

I believe it is the 2nd one its the most logical

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3 years ago

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Sixty out of every 100 pieces of candy is red. Which Indicates the

JulsSmile [24]

Answer:

The proportion of red candies is 60/100.

Step-by-step explanation:

Given that sixty out of every 100 pieces of candy is red, to determine which indicates the proportion of red candies, the following calculation must be performed:

60 red candies out of 100 total candies

60/100

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3 years ago

200 meters

Katyanochek1 [597]

Answer:

520 m

Step-by-step explanation:

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3 years ago

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

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3 years ago