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almond37 [142]
3 years ago
13

A ball rolls down a hill with a constant acceleration of 3.0 m/s.

Physics
1 answer:
lions [1.4K]3 years ago
5 0
Starting velocity (u) =0
acceleration (a) = 3
time (t) = 4
final velocity (v) =?

v=at+u
v=3(4)+0
v=12m/s2

distance (s) =?
s=0.5(u+v)(t)
s=0.5(0+12)3
s=18m
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If a woman needs an amplification of 1.0 ✕ 105 times the threshold intensity to enable her to hear at all frequencies, what is h
Damm [24]

Answer:

50 dB.

Explanation:

given,

Amplification needed by the woman,I= 1 x 10⁵ I₀

where as I₀ is the threshold frequency

overall hearing loss of the woman= ?

Using the equation of sound intensity level

\beta(dB) = 10 log(\dfrac{I}{I_0})

\beta(dB) = 10 log(\dfrac{1\times 10^5\ I_0}{I_0})

\beta(dB) = 10 log(1\times 10^5)

\beta(dB) = 50\ dB

The overall hearing loss of woman is equal to 50 dB.

7 0
4 years ago
If an object is the equal to the density of water will it float of sink?
castortr0y [4]
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4 0
3 years ago
n electric motor rotating a workshop grinding wheel at 1.10 102 rev/min is switched off. Assume the wheel has a constant negativ
Schach [20]

Answer:

Time taken to stop = 6 sec

Explanation:

Given:

Rotation of wheel = 1.10 × 10² rev/min

Final velocity (v) = 0

Angular acceleration (a) = - 1.92 rad/s²

Find:

Time taken to stop

Computation:

Initial velocity (u) = (1.10 × 10² × 2π rad) / 60 sec

Initial velocity (u) = 11.52 rad / sec

We know that,

V = U +at

t = (v-u)a

t = (0 - 11.52) / (-1.92)

Time taken to stop = 6 sec

3 0
3 years ago
It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the el
Aneli [31]

Answer:

P=4801.5

Explanation:

Given :

work done = W = 100,832 J

time = 21.0 sec

Find:

P = ?

Formula:

P = W/t

Solution:

P = W/t

P = 100,832/21.0

  =  4801.52 J/s or Watts

6 0
4 years ago
A spherical balloon has a radius of 6.95m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of ai
klio [65]

Answer:

602.27 kg

Explanation:

The computation of the largest mass of cargo the balloon can lift is shown below:-

Volume of helium inside the ballon= (4 ÷ 3) × π × r^3

= (4 ÷ 3) × 3.14 × 6.953

= 1406.19 m3

Mass the balloon can carry = volume × (density of air-density of helium)

= 1406.19 × (1.29-0.179)

= 1562.27 kg

Mass of cargo it can carry = Mass it can carry - Mass of structure

= 1562.27 - 960

= 602.27 kg

6 0
3 years ago
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