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3 years ago

Is the igneous rock destructive or constructive?

1 answer:

5 0

This certain type of rock is constructive, not only from the fact that it was made up from earthly habits. But also it breaks down very easily, which can help the environment. Therefore a sedimentary rock is constructive.

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Which item is dull.

DaniilM [7]

A cloth sock is dull; it doesn’t shine

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2 years ago

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Would Nitrogen Dioxide be ionic or covalent

tatiyna

Explanation:

The nitrogen dioxide is a covalent compound where one nitrogen is the central atom which is bonded to two oxygen atoms, where one oxygen atom is bonded by a single bond and other oxygen atom by a double bond.

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2 years ago

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I’ll mark brainliest <3<br> Can you just check to see if I have this right?

serious [3.7K]

Answer:

yes

Explanation:

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3 years ago

Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL

wlad13 [49]

Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity of solution of sodium sulfate.</h3>

In this case, you have:

number of moles of sodium sulfate= $5.2 grams\frac{1 mole}{142 grams} = 0.0366 moles$ (being 142 g/mole the molar mass of sodiums sulfate)
volume= 500 mL= 0.5 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{0.0366 moles}{0.5 L}$

Solving:

Molarity= 0.0732 $\frac{moles}{liter}$

Finally, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

Learn more about molarity:

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1 year ago

One mole of an ideal gas is contained in a cylinder with a movable piston. The temperature is constant at 77°C. Weights are remo

frozen [14]

Answer:

The total work is 4957.45J

Explanation:

For an ideal gas, at constant temperature the definition of work (W) is

$W = - P.dV = - n.R.T \int\limits^i_f {\frac{dV}{V} \\W = - n.R.T. Ln (\frac{V_{f}}{V_{I}})\\W = - n.R.T. Ln (\frac{P_{i}}{P_{f}})$

where P is the pressure, V the volume, n the moles number, T the temperature and R the gas constant.

To solve the problem is necessary to replace the two steps in the equation

Stape 1: n = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 5.50atm and Pf = 2.43atm.

$W_{1} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{5.50atm}{2.43atm}) = 23.44atm.Lx101.325\frac{J}{atm.L} =2375.44J$

Stape 2: n = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 2.43atm and Pf = 1.00atm.

$W_{2} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{2.43atm}{1.00atm}) = 25.48atm.Lx101.325\frac{J}{atm.L} =2582.01J$

The total work is the sum of the two steps

$W = W_{1} + W_{2} = 2375.44J + 2582.01J = 4957.45J$

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3 years ago