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weqwewe [10]
4 years ago
9

Is the igneous rock destructive or constructive?

Chemistry
1 answer:
sammy [17]4 years ago
5 0

This certain type of rock is constructive, not only from the fact that it was made up from earthly habits. But also it breaks down very easily, which can help the environment. Therefore a sedimentary rock is constructive.

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A solution is made by mixing 36. g of heptane (C_7H_16) and 16. g of chloroform (CHCl_3). Calculate the mole fraction of heptane
Diano4ka-milaya [45]

Answer:

Mole fraction of solute (heptane) → 0.73

Explanation:

Mole fraction = Moles of solute or solvent / Total moles

Let's calculate the moles of everything:

Moles of solute → Mass of solute / Molar mass

36 g / 100 g/mol = 0.36 moles

Moles of solvent → Mass of solvent / Molar mass

16 g / 119.35 g/mol = 0.134 moles

Total moles = 0.36 + 0.134 = 0.494 moles

Mole fraction of solute = 0.36 / 0.494 → 0.73

8 0
4 years ago
Which of the following has a bent molecular shape
ale4655 [162]

Answer:

The molecular shape of hydrogen sulfide is bent (H2s)

Explanation:

5 0
4 years ago
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Klio2033 [76]
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8 0
3 years ago
Read 2 more answers
Every reduction reaction MUST be accompanied by
Dafna1 [17]

Answer:

oxidation reaction.

Explanation:

Every reduction reaction must be accompanied by an oxidation reaction.

Oxidation leads electrons loss whereas reduction implies gain of electrons. So missing electrons should always be the equivalent of obtained electrons. Without something acquiring electrons there can't be any loss. Electrons can't simply disappear!

It implies, but, that oxidation and reduction must occur simultaneously at different locations and the electrons can commute across cables or in a liquid medium by ions.

7 0
3 years ago
__CH4+O2--&gt;__CO2+__H2O
Temka [501]

CH4 + 2O2 --> CO2 + 2H2O

On the reactant side you start with 1 carbon, 4 hydrogen, and 2 oxygen. On the product side you start with 1 carbon, 2 hydrogen, and 3 oxygen. In order to get them equal, you need to put 2 in front of the H2O which equals out the number of Hydrogen on both sides. But Now we must balance the Oxygens. Because of the H2O we now have 4 Oxygens on the product side and only 2 on the reactant. In order to balance this, we put a 2 in front of the O2 giving us 4 hydrogen on both sides, Balancing the equation

7 0
3 years ago
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