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kondor19780726 [428]
2 years ago
15

PLEASE HELP

Chemistry
2 answers:
Marysya12 [62]2 years ago
6 0

Answer:

Military

Explanation:

I may be wrong but military seems most likely

Maru [420]2 years ago
5 0

Answer: c or 3, "To react to Noriega's attacks".

Explanation: I got right in assignment 2021

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Gas law problem: A gas has a volume of 800 mL at -25℃ and 600 kPa. What would the volume of the gas be at 227℃ and 1000 kPa?
Sati [7]
<h3><u>Answer;</u></h3>

= 930.23 mL

<h3><u>Explanation</u>;</h3>

Using the combined gas law;

P1V1/T1 = P2V2/T2

Where; P1 = 600 kPa, V1 = 800 mL, and T1 = -25 +273 = 258 K, and

V2= ?, P2 = 1000 kPa, and T2 = 227 +273 = 500 K

Thus;

V2 = P1V1T2/T1P2

     = (600 ×800 ×500) / (258 × 1000)

     = 930.23 mL

5 0
3 years ago
Help. chemistry...........
nasty-shy [4]
<span>The </span>equilibrium<span> will </span>shift<span> to favor the side of the reaction that involves fewer moles of gas.
Its C

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8 0
3 years ago
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An ion from a given element has 24 protons and 22 electrons
musickatia [10]
Hi,

An ion with unequal number of protons and electrons haves a name. A name depends on whether there are more protons than electrons (CATION) or if there are more electrons than protons (ANION).

Hope this helps.
r3t40
8 0
3 years ago
A hydrogen atom has a diameter of about 10 nm. Express this diameter in micrometers, meters, and millimeters.
MariettaO [177]

1) 1 nm = 0.001 µm; one nanometer is equal to 0.001 (10⁻³) micrometer.

d(H) = 10 nm; diameter of hydrogen atom.

d(H) = 10 nm · 0.001 µm/nm.

d(H) = 0.01 µm = 10⁻² µm.

2) 1 nm = 10⁻⁹ m ; one meter is equal to 0.0000000001 (10⁻⁹) meter.

d(H) = 10 nm.

d(H) = 10 nm · 10⁻⁹ m/nm.

d(H) = 0.00000001 m = 10⁻⁸ m.

3) 1 nm = 10⁻⁶ mm ; one nanometer is equal to 0.000001 (10⁻⁶) millimeter.

d(H) = 10 nm · 10⁻⁶ mm/nm.

d(H) = 0.00001 mm = 10⁻⁵ mm.

4 0
3 years ago
Read 2 more answers
A 21.8 g sample of ethanol (C2H5OH) is burned in a bomb calorimeter, according to the following reaction. If the temperature ris
Blababa [14]

<u>Answer:</u> The heat capacity of calorimeter is 15.66J/^oC

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethanol = 21.8 g

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

\text{Moles of ethanol}=\frac{21.8g}{46.07g/mol}=0.473mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.473 moles

\Delta H_{rxn} = enthalpy change of the reaction  = -1235 kJ/mol = -1235\times 10^3J/mol     (Conversion factor:  1 kJ = 1000 J)

Putting values in above equation, we get:

-1235\times 10^3J/mol=\frac{q}{0.473mol}\\\\q=(-1235\times 10^3J/mol\times 0.473mol)=-584.16\times 10^3J

To calculate the heat capacity of calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed by the calorimeter = 584.16\times 10^3J

c = heat capacity = ?

\Delta T = change in temperature = T_2-T_1=62.3^oC-25^oC=37.3^oC

Putting values in above equation, we get:

584.16\times 10^3J=c\times 37.3^oC\\\\c=\frac{584.16\times 10^3J}{37.3^oC}=15.66J/^oC

Hence, the heat capacity of calorimeter is 15.66J/^oC

4 0
3 years ago
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