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2 years ago

PLEASE HELP

Chemistry

2 answers:

Marysya12 [62]2 years ago

6 0

Answer:

Military

Explanation:

I may be wrong but military seems most likely

Maru [420]2 years ago

5 0

Answer: c or 3, "To react to Noriega's attacks".

Explanation: I got right in assignment 2021

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1. The underlined portion of the chemical formula above is the _____ and it represents ____________________.

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2.No it is not balanced,oxygen is less than represented.

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3 years ago

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Scientists at a food manufacturing company compare the properties of substances for use in flavoring frozen yogurt. They prepare

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I pick but I'm not sure about it though 1and3

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2 years ago

An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr

Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

$C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa$

Rate of flow of ideal gas , n = 4 kmol/hr = $\frac{4\times 1000mol}{3600s}=1.11mol/s$ (Conversion factors used: 1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW (Conversion factor: 1 kW = 1000 W)

We know that:

$\Delta U=0$ (For isothermal process)

So, by applying first law of thermodynamics:

$\Delta U=\Delta q-\Delta W$

$\Delta q=\Delta W$ .......(1)

Now, calculating the work done for isothermal process, we use the equation:

$\Delta W=nRT\ln (\frac{P_1}{P_2})$

where,

$\Delta W$ = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

$P_1$ = initial pressure = 100 kPa

$P_2$ = final pressure = 50 kPa

Putting values in above equation, we get:

$\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW$

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

$\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW$

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

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2 years ago

The name of Earth's single, huge continent from over 250 million years ago is (1 point)

babunello [35]

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3 years ago

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An open "empty" 2 L plastic pop container, which has an actual inside volume of 2.05 L, is removed from a refrigerator at 5 °C a

Pani-rosa [81]

2.168 L of air will leave the container as it warms

<h3>Further explanation</h3>

Given

V₁=2.05 L

T₁ = 5 + 273 = 278 K

T₂ = 21 + 273 = 294 K

Required

Volume of air

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

$\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Input the value :

V₂=(V₁.T₂)/T₁

V₂=(2.05 x 294)/278

V₂=2.168 L

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3 years ago