1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kondor19780726 [428]
2 years ago
15

PLEASE HELP

Chemistry
2 answers:
Marysya12 [62]2 years ago
6 0

Answer:

Military

Explanation:

I may be wrong but military seems most likely

Maru [420]2 years ago
5 0

Answer: c or 3, "To react to Noriega's attacks".

Explanation: I got right in assignment 2021

You might be interested in
Drag each label to the correct location on the image identify the parts of the energy diagram
diamong [38]
If you would’ve attached a picture I’m sure it would’ve been a lot easier.
4 0
2 years ago
Read 2 more answers
Chuck has a very detailed model of the solar system where each planet is made out of granite rock. Since his little sister reall
Ilia_Sergeevich [38]

He could be blindfolded and know which was his and which was his sister's. All he would need to do is pick them both up and if they were too big then pick them up one at a time. The lumber might make it harder to tell, but this is a question about physical properties.

So there is a change in mass which for the purpose of this question should be  quite different. His sister's ought to be much lighter than his. He would find it easier to pick up.

8 0
3 years ago
Read 2 more answers
The diagram below show an enlarged view of the beams of a triple-beam balance
VLD [36.1K]

Answer:

1) 455.2 g. 2) 545.2 g.

Explanation:

i think this is right

6 0
2 years ago
How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?
Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0
3 years ago
Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.
MatroZZZ [7]
<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
 We know Ka for C6H5NH2 = 1.78x10^-11
  We have Kw = Ka x Kb => Ka = Kw / Kb
  => (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
 K^2 = 3 x 10^-12 => K = 1.73 x 10^-6.
 pH = -log(Kw(H3O^+)) = -log(1.73 x 10^-6) = 5.76</span>
6 0
3 years ago
Other questions:
  • Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymer
    8·1 answer
  • Q1. Which reaction represents the half-reaction of lead (Pb) and the SRP value that could be found on an electric potential tabl
    13·1 answer
  • A gas is contained in a thick-walled balloon. When the pressure changes from 319 mm Hg to 215 mm Hg, th volume changes from 0.55
    9·2 answers
  • Which reaction would cause an increase in entropy? A. SO2Cl2(g) SO2(g) + Cl2(g) B. PCl3(g) + Cl2(g) PCl5(g) C. 2CO(g) + O2(g) 2C
    15·2 answers
  • 3) <br> Which subatomic particle is NOT found at the center of the atom?
    13·1 answer
  • A gas container has an initial temperature of 348 K with an unknown pressure. When the temperature changes to 506 K the pressure
    11·1 answer
  • Identify one step in the water cycle that is driven by the force of gravity
    11·1 answer
  • Balance Reaction<br><br> K(s) + H2O(l) —&gt; KOH(aq) + H2
    6·1 answer
  • How many moles are in 30 mL water sample
    10·1 answer
  • What classifies a substance as an element?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!