Question

In outer space a five KG object moving in to the right at 4M/S and a two KG object moving to the left at 3MS collide and stick together their speed after the collision is

Answer 1

Answer:

Combined speed, V = 2 m/s

Explanation:

Given that,

Mass of object 1, m = 5 kg

Speed of object 1, u = 4 m/s (due right)

Mass of object 2, m' = 2 kg

Speed of object 2, u' = -3 m/s (due left)

Let V is the speed of the objects after the collision. Here, both objects stick to each other. Therefore, the momentum remains conserved. So,

$mu+m'u'=(m+m')V\\\\V=\dfrac{mu+m'u'}{(m+m')}\\\\V=\dfrac{5\times 4+2\times (-3)}{(5+2)}\\\\V=2\ m/s$

So, the combined speed of the masses will be 2 m/s.