<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>
- A certain circuit is composed of two series resistors
- The total resistance is 10 ohms
- One of the resistor is 4 ohms
<h3>
<u>To </u><u>Find </u><u>:</u><u>-</u></h3>
- We have to find the value of other resistor?
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
We know that,
In series combination,
- When a number of resistances are connected in series, the equivalent I.e resultant resistance is equal to the sum of the individual resistances and is greater than any individual resistance
<u>That </u><u>is</u><u>, </u>
Rn in series = R1 + R2 + R3.....So on
<u>Therefore</u><u>, </u>
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
We have,
R1 + R2 = 10 Ω
4 + R2 = 10Ω
R2 = 10 - 4
R2 = 6Ω
Hence, The value of R2 resistor in series is 6Ω
Answer:
yes you are totally right
Answer:
Angular velocity is same as frequency of oscillation in this case.
ω =
x ![[\frac{L^{2}}{mK}]^{3/14}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BL%5E%7B2%7D%7D%7BmK%7D%5D%5E%7B3%2F14%7D)
Explanation:
- write the equation F(r) = -K
with angular momentum <em>L</em>
- Get the necessary centripetal acceleration with radius r₀ and make r₀ the subject.
- Write the energy of the orbit in relative to r = 0, and solve for "E".
- Find the second derivative of effective potential to calculate the frequency of small radial oscillations. This is the effective spring constant.
- Solve for effective potential
- ω =
x ![[\frac{L^{2}}{mK}]^{3/14}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BL%5E%7B2%7D%7D%7BmK%7D%5D%5E%7B3%2F14%7D)
Answer:
the weight is 49.1 N
Explanation:
The computation of the weight is shown below:
As we know that
= 5kg of potatoes × gravitational acceleration
= 5kg of potatoes × 9.82 m/s
= 49.1 N
Hence, the weight is 49.1 N
We simply applied the above formula in order to determine the weight