All categories

3 years ago

The area of land where water is drained downhill into a body of water is known as a drainage basin, or _______.

Physics

2 answers:

o-na [289]3 years ago

8 0

Answer: Watershed

A watershed or drainage basin is a down the slope land where the water is drained off from sources of water flowing comparatively at some elevation. It includes water from rivers, river streams that progressively drain into larger areas. The initial source of watershed is called as headwater. The endpoint of watershed is open up into another water body is called as mouth.

GenaCL600 [577]3 years ago

6 0

Water sheds i hope this helps give me a brainiest answer

You might be interested in

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th

Igoryamba

A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find the velocity and the speed when t = 4. f(t) = 12t² + 35 t + 1

Answer:

Velocity = 131 m/s

Speed = 131 m/s

Explanation:

Equation of motion, s = f(t) = 12t² + 35 t + 1

To get velocity of the particle, let us find the first derivative of s

v (t) = ds/dt = 24t + 35

At t = 4

v(4) = 24(4) + 35

v(4) = 131 m/s

Speed is the magnitude of velocity. Since the velocity is already positive, speed is also 131 m/s

5 0

2 years ago

A ball is dropped from a cliff. determine how far the ball fell after 7.5 seconds

grin007 [14]

Answer:

The ball fell 275.625 meters after 7.5 seconds

Explanation:

If an object is left on free air (no friction), it describes an accelerated motion in the vertical direction, powered exclusively by the acceleration of gravity. The formulas needed to compute the different magnitudes involved are

$V_f=gt$

$\displaystyle y=\frac{gt^2}{2}$

Where $V_f$ is the final speed of the object in free fall, assumed positive downwards, t is the time elapsed since the release and y is the vertical distance traveled by the object

The ball was dropped from a cliff. We need to calculate the vertical distance the ball went down in t=7.5 seconds. We'll use the formula

$\displaystyle y=\frac{gt^2}{2}$

$\displaystyle y=\frac{(9.8)(7.5)^2}{2}$

$Y=275.625\ m$

5 0

3 years ago

a runner starts from rest and has an acceleration of 3 m/s^2. How fast is she running after 1.1 seconds

grigory [225]

Acceleration x time = velocity

Since you're given acceleration and time, just plug the values into the equation.

3 $\frac{m}{s^{2}}$ x 1.1 s = ?

Solve that equation, and remember your velocity should be in m/s.

8 0

2 years ago

If an object accelerates from rest, what will its velocity be after 1.3 s if it has a constant acceleration of 9.1 m/s^2?

HACTEHA [7]

$\text{Given that,}\\\\\text{Initial velocity,} ~v_0 = 0~ \text{m~s}^{-1}\\\\\text{Time, t = 1.3~sec}\\\\\text{Acceleration, a = 9.1 m s}^{-2}\\\\\\\\\text{Velocity,}\\\\v = v_0 +at\\\\\implies v = 0 + 9.1 \times 1.3 = 11.83~~ \text{m~s}^{-1}$

5 0

2 years ago

Artemon [7]

Answer:

constant volicty of the pumper when they hit ground 7.03-/s

8 0

3 years ago