Question

Un transformador reductor se usa para convertir un voltaje alterno de 10000 V a 500V ¿Cuál deberá ser la razón (N1/N2) entre las espiras si la corriente en el primario es de 1 amp. Y el transformador tiene un rendimiento del 100%. ¿Cuál es la corriente de salida?

Answer 1

Answer:

(a). The value of $\dfrac{N_{1}}{N_{2}}$ is $\dfrac{1}{20}$

(b). The output current is 0.05 A

Explanation:

Given that,

Secondary voltage = 10000 V

Primary voltage = 500 V

Primary current = 1 A

(a). We need to calculate the value of $\dfrac{N_{1}}{N_{2}}$

Put the value into the formula

$\dfrac{V_{s}}{V_{p}}=\dfrac{N_{2}}{N_{1}}$

$\dfrac{N_{1}}{N_{2}}=\dfrac{V_{p}}{V_{s}}$

Put the value into the formula

$\dfrac{N_{1}}{N_{2}}=\dfrac{500}{10000}$

$\dfrac{N_{1}}{N_{2}}=\dfrac{1}{20}$

(b). We need to calculate the output current

Using formula of current

$\dfrac{I_{s}}{I_{p}}=\dfrac{N_{1}}{N_{2}}$

$I_{s}=I_{p}\times\dfrac{N_{1}}{N_{2}}$

Put the value into the formula

$I_{s}=1\times\dfrac{1}{20}$

$I_{s}=0.05\ A$

Hence, (a). The value of $\dfrac{N_{1}}{N_{2}}$ is $\dfrac{1}{20}$

(b). The output current is 0.05 A