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-Dominant- [34]
3 years ago
13

Taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.

Physics
1 answer:
Gnoma [55]3 years ago
8 0

Answer:

1.5 \Omega

Explanation:

The resistance of a wire is given by:

R=\frac{\rho L}{A}

where

\rho is the resistivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

For the wire in this problem:

\rho = 3.3\cdot 10^{-7} \Omega m

L = 7.0 m

r = d/2 = 0.07 cm = 0.0007 m, so the area is

A=\pi r^2=\pi(0.0007)^2=1.54\cdot 10^{-6}m^2

Solving for R,

R=\frac{(3.3\cdot 10^{-7})(7.0)}{1.54\cdot 10^{-6}}=1.5 \Omega

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