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3 years ago

An atom has an atomic number 17 and atomic mass number 35. How many neutrons are present in its nucleus?

2 answers:

7 0

The number of neutrons that are present in its nucleus is 18. The correct option among all the options that are given in the question is the second option or option "B". Mass number minus the atomic number gives the number of neutrons. I hope that this is the answer that has come to your help.

n200080 [17]3 years ago

7 0

The answer is option B. 18 ..

(no. of neutrons= mass no. - atomic no. )

Hope it helps !!!

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Which of the following quantities is inversely proportional to the gravitational pull between two objects?

Contact [7]

Answer:

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

I hope this helps a little bit

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2 years ago

Read 2 more answers

2560 meters in 60 seconds, what is his average speed (velocity)

jok3333 [9.3K]

42.6 is the answer I believe because you would do 2,560 divided by 60 if I'm correct.

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3 years ago

Vitamins and iron are nutrients that provide energy to the human body. A true B false

SIZIF [17.4K]

I think it is A. but then you can also produce your own energy

4 0

3 years ago

Two remote control cars with masses of 1.16 kilograms and 1.98 kilograms travel toward each other at speeds of 8.64 meters per s

Black_prince [1.1K]

The initial momentum of the system can be expressed as,

$p_i=m_1u_1+m_{2_{}}u_2$

The final momentum of the system can be given as,

$p_f=m_1v_1+m_{2_{}}v_2$

According to conservation of momentum,

$p_i=p_f$

Plug in the known expressions,

$\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_2v_2=m_1u_1+m_2u_2-m_1v_1 \\ v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2} \end{gathered}$

Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.

Plug in the known values,

$\begin{gathered} v_2=\frac{(1.16\text{ kg)(8.64 m/s)+(1.98 kg)(-3.34 m/s)-(1.16 kg)(-2.16 m/s)}}{1.98\text{ kg}} \\ =\frac{10.02\text{ kgm/s-}6.61\text{ kgm/s+}2.51\text{ kgm/s}}{1.98\text{ kg}} \\ =\frac{5.92\text{ kgm/s}}{1.98\text{ kg}} \\ \approx2.99\text{ m/s} \end{gathered}$

Thus, the final velocity of second mass is 2.99 m/s.

3 0

1 year ago

BRAINLIEST AND MAY DOUBLE POINTS!!!

raketka [301]

Given that:

Energy of bulb (Work ) = 30 J,

Time (t) = 3 sec

The power consumption = ?

We know that, Power can be defined as rate of doing work

Power (P) = Work(Energy supplied) ÷ time

= 30 ÷ 3

= 10 Watts

The power consumption is 10 W.

3 0

3 years ago