Question

07.03 LC)

Answer 1

$Question \ 1)$  

$Probability \ is \ simply \ how \ likely \ something \ is \ to \ happen.$
$We \ get \ the \ probabilities \ by \ dividing \ the \ frequencies \ by \ the \ total.$
$The \ probability \ of \ an \ event \ can \ only \ be \ between \ 0 \ and \ 1$$and \ can \ also \ be \ written \ as \ a \ percentage.$ 

$The \ best \ example \ for \ understanding \ probability \ is \ flipping \ a \ coin: There are two possible outcomes ------\ \ heads or tails.$

$Probability \ is \ always \ out \ of 100 \%$ 

$\dfrac{P}{100\%}$ 

$20\% = \dfrac{20}{100} = 0.20 \ as \ a \ decimal$ 

$0.2 * 500 = 100$ 

$Question \ 2)$   $x+y+z=24$ 

$7+8+9 = 24 =\ \textgreater \ Number \ of \ roses$ 

$\dfrac{9}{24} * \dfrac{8}{23} = \dfrac{72}{552}$ 

$Question \ 3)$ 

$5 = Number \ of \ 2$ 

$100 = Total$ 

$=\ \textgreater \ \dfrac{5}{100}$ 

$Question \ 4)$  $x+y+z=16$ 

$1 + 5 + 10 = 16, Total \ Number$ 

$\dfrac{10}{16}* \dfrac{9}{15}$ $= Solution$ 

Answer 2

$Q1.\\p\%=\dfrac{p}{100};\ 20\%=\dfrac{20}{100}=0.20=0.2\\\\20\%-French\ of\ 500\ people\\\\0.2\cdot500=100\leftarrow Answer$


$Q2.\\\dfrac{white}{all}\cdot\dfrac{yellow}{all-1}\\\\7+8+9=24-number\ of\ all\ roses\\\\\dfrac{9}{24}\cdot\dfrac{8}{24-1}=\dfrac{9}{24}\cdot\dfrac{8}{23}=\dfrac{72}{552}\leftarrow Answer$


$Q3.\\5-number\ of\ 2\\100-number\ of\ all\\\\\dfrac{5}{100}\leftarrow Answer$


$Q4.\\1+5+10=16-number\ of\ all\ marbles\\\\\dfrac{10}{16}\cdot\dfrac{10-1}{16-1}=\dfrac{10}{16}\cdot\dfrac{9}{15}\leftarrow Answer$