La razon es la.división de dos números

1 answer:

4 0

Lo que se divide se llama dividendo, que se divide por el divisor, y el resultado se llama cociente. En el ejemplo, 20 es el dividendo, 5 es el divisor y 4 es el cociente.

You might be interested in

a vial of medicine contains 76 fluid ounces of medicine. If one dose consists of 2 fluid ounces how many doses does the vial con

Fudgin [204]

Then it contains 38 doses becasue 76 divide 2 is 38

7 0

3 years ago

Please help how to solve

lapo4ka [179]

82 is your answer , I subtracted 52-40 and got 12 , so I know that the RC side is 12 more than 70.

4 0

3 years ago

Find the L.C.M of 150,180and 240 leaving your answer as product of prime factors

Katarina [22]

Answer:

2^4·3²·5² = 3600

Step-by-step explanation:

3 0

3 years ago

Is this a function??????????

Virty [35]

This is a function because it passes the vertical line test.

Hope this Helps!!
~Kiwi

4 0

4 years ago

On the average,1% of a specific engine componentis found to not perform to standards when tested at the engine assembly plant. F

sasho [114]

Answer: 0.07938

Step-by-step explanation:

Let X be a binomial variable that represents the components of a specific engine.

As per given , the probability of componentis found to not perform to standards : p= 1%=0.01

Binomial probability formula :

$P(X=x)=\ ^nC_xp^x(1-p)^{n-x}$

Sample size : n= 100

If more than two are found to be non-performing the entire shipment is returned.

Now, Required probability : $P(X>2)=1-P(X\leq 2)$

$=1-(P(X=0)+P(X=1)+P(X=2))\\\\=1- (^{100}C_{0}(0.01)^0(0.99)^{100}+^{100}C_{1}(0.01)^{1}(0.99)^{99}+^{100}C_{2}(0.01)^{2}(0.99)^{98})\\\\=1-((0.99)^{100}+(100)(0.01)(0.99)^{99}+\dfrac{100!}{2!98!}(0.01)(0.99)^98)\\\\=1-(0.36603+0.36973+0.18486)\\\\=1-(0.92062)\\\\=0.07938$

So, the probability that a shipment is returned = 0.07938

3 0

4 years ago