Subtract 55 from the sum of 243 and 8

1)The computer accessory that Joanne is considering

ankoles [38]

Answer:

Check Explanation.

Step-by-step explanation:

- A sample space includes all the possible outcomes of a statistical event. It refers to all the possible results, values that a statistical event can take on.

- Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

a) Joanne is considering selling a computer accessory at her store and the accessories come in white, beige, gray or black and as an optical mouse, mechanical mouse or trackball.

This means that an accessory can be white and an optical mouse, white and a mechanical mouse or white and a trackball.

This can be done for the 3 other colours.

So, the sample space for the accessory spans:

(white, optical mouse), (white, mechanical mouse), (white, trackball), (beige, optical mouse), (beige, mechanical mouse), (beige, trackball), (gray, optical mouse), (gray, mechanical mouse), (gray, trackball), (black, optical mouse), (black, mechanical mouse), (black, trackball)

The probability that someone gets beige and a mechanical mouse

Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

Number of outcomes with an accessory that is beige and a mechanical mouse = 1

Number of events in the sample space = 12

The probability that someone gets beige and a mechanical mouse = (1/12) = 0.0833

b) Jackie has three pairs of jeans: Joe Brand, Levis and Seven. She also has 4 tops: red, blue, purple and pink.

The sample space for Jackie's outfits is;

(Joe Brand, red), (Joe Brand, blue), (Joe Brand, purple), (Joe Brand, pink), (Levis, red), (Levis, blue), (Levis, purple), (Levis, pink), (Seven, red), (Seven, blue), (Seven, purple), (Seven, pink)

The chance she wears the Joe Brand or Levis and a purple top.

Number of outcomes with an outfit of Joe Brand or Levis and a purple top = 2

number of outfits on the sample space = 12

The chance she wears the Joe Brand or Levis and a purple top = (1/6) = 0.1667

c) A surfer owns 5 wetsuits: brown, black, pants, shorts and green. He also owns 3 surf boards: blue, green and red.

Sample space includes

(brown, blue), (brown, green), (brown, red), (black, blue), (black, green), (black, red), (pants, blue), (pants, green), (pants, red), (shorts, blue), (shorts, green), (shorts, red), (green, blue), (green, green), (green, red)

The chance he has a green wetsuit and surfboard

Number of outcomes in the sample space with green wetsuit and a green surfboard = 1

number of outcomes in the sample space = 15

The chance he has a green wetsuit and surfboard = (1/15) = 0.0667

Hope this Helps!!!

4 0

3 years ago

Please help fast its quiz. :(

dezoksy [38]

Answer:

What is the question??

Thank you for the points

8 0

2 years ago

Read 2 more answers

Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin

julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

$\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}$

Recall that since both lines are parallel, we have that,

$m_1=m_2$

Thus

$m_2\text{ = 1}$

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

$\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 , y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}$

5 0

1 year ago

A giraffe is standing 22 feet from a naturalist hiding in the bush. The naturalist sights the animal and finds the angle of elev

kaheart [24]

Tan(angle) = opposite leg/ adjacent leg

Tan(30) = x/22

X = 22 * tan(30 )

X = 12.701 feet.

Round as needed

3 0

3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

So

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$