Plsss need help really bad

When the grounded conductor is to be spliced in a 12-inch by 12-inch junction box, there shall be at least ? of free conductor l

slamgirl [31]

There should be a 6" free conductor left for splicing

Why there should be 6" splicing?

You must leave the junction box with at least six inches of free conductor wiring when running electrical cables from the box to the box for connecting needs.

Actually, 6-8 inches can be left when running the electric cables, additionally even if the grounded conductor is to be spliced in a 12-inch by 12-inch.

Conductor splicing: A splice, which can be finished using either the crimping or soldering method, is the joining of two or more conductors in a way that produces a permanent electrical termination and mechanical link.

Hence we can conclude that 6 inches is fine for the conductor splicing

To learn more about splicing
brainly.com/question/7668842
#SPJ4

7 0

1 year ago

que sabemos de la revolución industrial y como ese proceso impulso el uso de los controles eléctricos en las industrias

Alex Ar [27]

Answer:

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Explanation:

8 0

3 years ago

Consider a Carnot refrigeration cycle executed in a closed system in the saturated liquid–vapor mixture region using 1.06 kg of

Alexxandr [17]

Answer:

$P_m_i_n = 442KPA$

Explanation:

We are given:

m = 1.06Kg

$T_H = 1.2T_L$

T = 22kj

Therefore we need to find coefficient performance or the cycle

$COP_R = \frac {1}{(T_R/T_l) -1}$

$= \frac {1 }{1.2-1}$

= 5

For the amount of heat absorbed:

$Q_l = COP_R Wm$

= 5 × 22 = 110KJ

For the amount of heat rejected:

$Q_H = Q_L + W_m$

= 110 + 22 = 132KJ

[tex[ q_H = \frac{Q_L}{m} [/tex];

= $= \frac{132}{1.06}$

= 124.5KJ

Using refrigerant table at hfg = 124.5KJ/Kg we have 69.5°c

Convert 69.5°c to K we have 342.5K

To find the minimum temperature:

$T_L = \frac{T_H}{1.2}$ ;

$T_L = \frac{342.5}{1.2}$

= 285.4K

Convert to °C we have 12.4°C

From the refrigerant R -134a table at $T_L$ = 12.4°c we have 442KPa

6 0

3 years ago

A metal specimen with an original diameter of 0.50 in. and a gauge length of 2.75 in. is tested in tension until a fracture occu

tatiyna

Answer:

Percent Elongation = 52.72%

Percent Reduction in Area = 64%

Explanation:

First we find percent elongation:

Percent Elongation = {Final Gage Length - Initial Gauge Length/Initial Guage Length} x 100%

Percent Elongation = {(4.20 in - 2.75 in)/2.75 in} x 100%

<u>Percent Elongation = 52.72%</u>

Now, for the percent reduction in area:

Percent Reduction in Area = {Final Cross Sectional Area - Initial Cross Sectional Area|/Initial Cross Sectional Area Length} x 100%

Percent Reduction in Area = {π(0.3 in)² - π(0.5 in)²/π(0.5 in)²} x 100%

<u>Percent Reduction in Area = - 64%</u>

here, negative sign shows a decrease in area.

5 0

3 years ago

What is the real name of the town that Bud & Bugs stayed in while they were waiting for the train?

Leona [35]

Answer: Hooverville

Explanation:

Bud, not Buddy is a book about a ten years old boy who ran away from home where he stayed with his foster parents. He was treated unfairly and beaten.

He left home to seek a better living and hope that he will find his father as well. He met another orphan named Bugs and they decided to go to Hooverville so that they can get a train going to California.

6 0

3 years ago