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Sunny_sXe [5.5K]
3 years ago
10

Consider a Carnot refrigeration cycle executed in a closed system in the saturated liquid–vapor mixture region using 1.06 kg of

refrigerant-134a as the working fluid. It is known that the maximum absolute temperature in the cycle is 1.2 times the minimum absolute temperature, and the net work input to the cycle is 22 kJ. If the refrigerant changes from saturated vapor to saturated liquid during the heat rejection process, determine the minimum pressure in the cycle.
Engineering
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

P_m_i_n = 442KPA

Explanation:

We are given:

m = 1.06Kg

T_H = 1.2T_L

T = 22kj

Therefore we need to find coefficient performance or the cycle

COP_R = \frac {1}{(T_R/T_l) -1}

= \frac {1 }{1.2-1}

= 5

For the amount of heat absorbed:

Q_l = COP_R Wm

= 5 × 22 = 110KJ

For the amount of heat rejected:

Q_H = Q_L + W_m

= 110 + 22 = 132KJ

[tex[ q_H = \frac{Q_L}{m} [/tex];

= = \frac{132}{1.06}

= 124.5KJ

Using refrigerant table at hfg = 124.5KJ/Kg we have 69.5°c

Convert 69.5°c to K we have 342.5K

To find the minimum temperature:

T_L = \frac{T_H}{1.2};

T_L = \frac{342.5}{1.2}

= 285.4K

Convert to °C we have 12.4°C

From the refrigerant R -134a table at T_L = 12.4°c we have 442KPa

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A polyethylene rod exactly 10 inches long with a cross-sectional area of 0.04 in2 is used to suspend a weight of 358 lbs-f (poun
Nadya [2.5K]

Answer:

Final length of the rod = 13.90 in

Explanation:

Cross Sectional Area of the polythene rod, A = 0.04 in²

Original length of the polythene rod, l = 10 inches

Tensile modulus for the polymer, E = 25,000 psi

Viscosity, \eta = 1*10^{9} psi -sec

Weight = 358 lbs - f

time, t = 1 hr = 3600 sec

Stress is given by:

\sigma = \frac{Force}{Area} \\\sigma = \frac{358}{0.04} \\\sigma = 8950 psi

Based on Maxwell's equation, the strain is given by:

strain = \sigma ( \frac{1}{E} + \frac{t}{\eta} )\\Strain = 8950 ( \frac{1}{25000} + \frac{3600}{10^{9} } )\\Strain = 0.39022

Strain = Extension/(original Length)

0.39022 = Extension/10

Extension = 0.39022 * 10

Extension = 3.9022 in

Extension = Final length - Original length

3.9022 =  Final length - 10

Final length = 10 + 3.9022

Final length = 13.9022 in

Final length = 13.90 in

7 0
3 years ago
Technician A says that weld-on dent removal attachments may be used on a steel panel.
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2 years ago
Let’s define a new language called dog-ish. A word is in the lan- guage dog-ish if the word contains the letters ’d’, ’o’, ’g’ a
attashe74 [19]

Answer and Explanation:

// code

class Main {

   public static void main(String[] args) {

       /*

        *

        *

        * your code

        *

        */

       System.out.println(inDogish("aplderogad"));

       System.out.println(inXish("aplderogad", "dog"));

   }

   // returns true if the word is in dog-ish

   // returns false if word is not in dog-ish

   public static boolean inDogish(String word) {

       // first find d

       if (dogishHelper(word, 'd')) {

           // first find string after d

           String temp = word.substring(word.indexOf("d"));

           // find o

           if (dogishHelper(temp, 'o')) {

               // find string after o

               temp = temp.substring(temp.indexOf("o"));

               // find g

               if (dogishHelper(temp, 'g'))

                   return true;

           }

The output is attached below

       }

       return false;

   }

   // necessary to implement inDogish recursively

   public static boolean dogishHelper(String word, char letter) {

       // end of string

       if (word.length() == 0)

           return false;

       // letter found

       if (word.charAt(0) == letter)

           return true;

       // search in next index

       return dogishHelper(word.substring(1), letter);

   }

   // a generalized version of the inDogish method

   public static boolean inXish(String word, String x) {

       if (x.length() == 0)

           return true;

       if (word.length() == 0)

           return false;

       if (word.charAt(0) == x.charAt(0))

           return inXish(word.substring(1), x.substring(1));

       return inXish(word.substring(1), x.substring(0));

   }

}

PS E:\fixer> java Main true true ne on

PS E:\fixer> java Main true true ne on

5 0
3 years ago
If your web site contains ____________, searching for problems and errors is much easier and faster.
finlep [7]

If your web site contains specific codes searching for problems and errors is much easier and faster.

Explanation:

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  • The term Specific Code makes work faster and precise.
  • Just enter the coding, then all the errors and problems will be displayed.
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3 0
3 years ago
The horizontal component of acceleration, ay during a projectile motion is usually assumed to be_________ a)-9.81 m/s^2 b)-Zero
Alenkinab [10]

Answer:

b) zero

Explanation:

The horizontal component of acceleration during projectile motion is usually assumed to be zero.Because in projectile motion horizontal component of velocity will remain the constant and we know that rate of change of velocity with time is called acceleration.So when velocity is constant then acceleration will be zero.

In projectile motion ,gravitational acceleration will be in only vertical direction.

6 0
3 years ago
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