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4 years ago

10

Would you expect trna or mrna to be more extensively hydrogen bonded? Why?

1 answer:

AveGali [126]4 years ago

4 0

Answer:

tRNA

Explanation:

Messenger RNA is formed by a single chain of nucleotides, in contrasting to DNA, that has a double helix connoting several hydrogen bonds between chains. In this case mRNA doesn't compete with DNA hydrogen bonds, because it appears in a single chain.

In the case of tRNA, their secondary structure present domains with abundant hydrogen bonds forming hairpins, loops, bulges and so. In this way more interactions en the same molecule (tRNA) exist in different of their parts.

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Calculate number of moles present in 2.3g

Natalija [7]

Explanation:

idk if that's the actual answer but I hope it helps (:

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3 years ago

You put scruffy can run up to 2 meters/sec on his fastest days scruffy has a mass of 8 KG what is his maximum kinetic energy on

ale4655 [162]

Answer:

E = 16 J

Explanation:

We have,

You put scruffy can run up to 2 m/s on his fastest days scruffy has a mass of 8 kg

It is required to find the maximum kinetic energy on his fastest days. If v is the velocity, then kinetic energy is given by :

$E=\dfrac{1}{2}mv^2$

Plugging all the values,

$E=\dfrac{1}{2}\times 8\times 2^2 \\\\E=16\ J$

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4 years ago

True/False Chemistry

PSYCHO15rus [73]

Answer:true

Explanation:

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3 years ago

A certain large pond had many plants growing in it. It also had a population of fish living in it. One day, a chemical spilled i

DaniilM [7]

Answer:

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Explanation:

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3 years ago

How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

max2010maxim [7]

Answer: A volume of 600 mL of 3.0 M $H_{2}SO_{4}$ solution can be prepared by using 100.0 mL OF 18 M $H_{2}SO_{4}$ .

Explanation:

Given: $V_{1}$ = ?, $M_{1} = 3.0 M\\$

$V_{2} = 100.0 mL$ , $M_{2} = 18 M$

Formula used to calculate the volume is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\3.0 M \times V_{1} = 18 M \times 100.0 mL\\V_{1} = \frac{18 M \times 100.0 mL}{3.0M}\\= 600 mL$

Thus, we can conclude that a volume of 600 mL of 3.0 M $H_{2}SO_{4}$ solution can be prepared by using 100.0 mL OF 18 M $H_{2}SO_{4}$ .

6 0

3 years ago