Answer:
pOH = -log[OH-]
log x =a <=> 10ª = x
so, if pOH is 10.75, we need to aply the anti log of it to get the [OH-], where x is [OH-] and a is pOH
using the calc, we have
-log [OH-] = 10.75 <=>10^(-10.75) = [OH-]
[OH-]= 1.78 x 10^(-11)
Answer:
i think you should ask for the google
Answer:
The number of solute particles increases, and the boiling point increases.
Explanation:
- It is known from colligative properties that adding solute to the solvent will cause elevation of boiling point.
- Elevation of boiling point (ΔTb) can be expressed as:
<em>ΔTb = Kb.m,</em>
where, Kb molal boiling point elevation constant.
m is the molal concentration of solute.
- Adding more sodium chloride to the solution:
will increase the number of solute particles and also will increase the molal concentration of NaCl solute.
<em>∵ ΔTb ∝ m.</em>
- So, the boiling point increases.
- Thus, the right choice is:
<em>The number of solute particles increases,</em>
<em></em>
Answer:
correct answers:
objecting to a local and consent bill
chubbing
filibuster
incorrect answers:
amending legislation
vetoing legislation
Explanation:
Answer:
0.250 mol Mg²⁺
0.500 mol Cl⁻
Explanation:
Magnesium chloride (MgCl₂) dissociates into ions according to the following equilibrium:
MgCl₂ ⇒ Mg²⁺ + 2 Cl⁻
1 mol 1 mol 2 mol
1 mol of Mg²⁺ and 2 moles of Cl⁻ are formed per mole of MgCl₂. If we have 0.250 mol of MgCl₂, the following amounts of ions will be formed:
0.250 mol MgCl₂ x 1 mol Mg²⁺/mol MgCl₂= 0.250 mol Mg²⁺
0.250 mol MgCl₂ x 2 mol Cl⁻/mol MgCl₂= 0.500 mol Cl⁻