<span>X+2y=4 3z=-3 x+2y-z=1 becomes
</span><span>X+2y=4
3z=-3
x+2y-z=1
If 3z= -3, then z = -1.
Then we have
</span>X+2y=4 => x+2y = 4
3z=-3
x+2y-z=1 => x+2y-(-1)=1 => x+2y = 0
The graphs of these two straight lines never cross, so the system has NO SOLUTION.
For number 7 since the rational number is countable, and the set of real numbers is uncountable, almost all real numbers are irrational. So you should choose false
8 yes! All whole numbers are integers. For an example 0 is a whole number, 0 Is ALSO a integer. So you should choose truth
Answer:
Step-by-step explanation:
Are you sure you wrote the question correctly? If I'm doing this right, none of the answers provided are correct.
Step-by-step explanation:
1. 10-(2+3) = 5
2. 2x3 - 10 = -4
3. 3 x (4-2) = 6
4. (3+5) / 4 = 2
5. (5-2) x 3 = 9
6. (9-4) + 5 = 10