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Tems11 [23]
3 years ago
10

Which of the following is the correctly balanced equation for the incomplete combustion of heptene, C7H14? Please explain how yo

u got the answer.
2C7H14+ 21O2→ 14CO2+ 14H2O

C7H14+ O2→ C7O2+ 7H2

C7H14+ 7O2→ 7CO + 7H2O

C7H14+ 14O → 7CO + 7H2O
Chemistry
2 answers:
Eva8 [605]3 years ago
8 0

Answer: C₇H₁₄ + 7O₂ → 7CO + 7H₂O

Explanation:

  • For any equation to be balanced the number of (C, H, and O) atoms in the reactants side should be the same in the products side.
  • The first choice is wrong because it is unbalanced equation that the reactants side has 22 O atoms and in the products side there is 14 O atoms.
  • The second choice is wrong because the incomplete combustion of heptene results CO and/or CO₂ and H₂O.
  • The third choice is the right answer that it has 7 atoms of C, 14 atoms of H, and 14 atoms of O in both reactants and products sides.
  • The fourth choice is wrong because the combustion of heptene occurs in O₂ not in O.
Hoochie [10]3 years ago
4 0

Answer : The correct balanced equation will be,

C_7H_{14}+7O_2\rightarrow 7CO+7H_2O

Explanation :

Balanced chemical equation : It is the number of atoms of individual elements present on reactant side must be equal to the number of atoms of individual elements present on product side.

As we know that the hydrocarbons can undergo complete or incomplete combustion that depends on the amount of oxygen available.

Complete combustion : It takes place when there is a good supply of oxygen. In this, hydrocarbon react with the oxygen to give carbon dioxide and water as a product.

Incomplete combustion : It takes place when there is a poor supply of oxygen. In this, hydrocarbon react with the oxygen to give carbon monoxide, carbon and water as a product.

As per question, the incomplete combustion of heptene react with oxygen to give carbon monoxide and water as a product.

Therefore, the balanced chemical reaction will be :

C_7H_{14}+7O_2\rightarrow 7CO+7H_2O

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Explain obser made when flourine is bubbled in bromine water for sometime
lisabon 2012 [21]

Explanation:

Alkenes react in the cold with pure liquid bromine, or with a solution of bromine in an organic solvent like tetrachloromethane. The double bond breaks, and a bromine atom becomes attached to each carbon. The bromine loses its original red-brown color to give a colorless liquid. In the case of the reaction with ethene, 1,2-dibromoethane is formed.

5 0
3 years ago
In part A, when you added water to the sodium acetate in the flask, some of the chemical dissolved into the water. Would you cal
viktelen [127]

Answer: The solution is a SATURATED solution.

Explanation:

Although most substances are soluble in water, some are more soluble than others,that is , their solubilities differ. SOLUBILITY is a means of comparing the extent to which different solutes can dissolve in a particular solvent at a definite temperature.

From the question above, when water was added to the sodium acetate in the flask, SOME of the chemical dissolved into the water, meaning that some remained undissolved. This is because a given volume of water can only dissolve a certain amount of chemical in it at room temperature. If more chemical is added to such a solution, the chemical will remain undissolved. Such a chemical solution is said to be a SATURATED SOLUTION.

A saturated solution of a solute at a particular temperature is on which contains as much solute as it can dissolve at that temperature in the presence of undissolved solute particles.

Unsaturated solution is a type of solution that dissolves all its solutes with no presence of undissolved solute.

Supersaturated solution is one which contains more of the solute than it can normally hold at that temperature. It is an unstable solution which crystallizes out when disturbed.

4 0
3 years ago
Read 2 more answers
Question
madam [21]

Answer:

The specific heat of the metal is 2.09899 J/g℃.

Explanation:

Given,

For Metal sample,

mass = 13 grams

T = 73°C

For Water sample,

mass = 60 grams

T = 22°C.

When the metal sample and water sample are mixed,

The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the  addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.

Since, heat lost by metal is equal to the heat gained by water,

Qlost = Qgain

However,

Q = (mass) (ΔT) (Cp)

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

After mixing both samples, their temperature changes to 27°C.

It implies that , water sample temperature changed from  22°C to 27°C and metal sample temperature changed from 73°C to 27°C.

Since, Specific heat of water = 4.184 J/g°C

Let Cp be the specific heat of the metal.

Substituting values,

(13)(73°C - 27°C)(Cp) = (60)(27°C - 22℃)(4.184)

By solving, we get Cp =

Therefore, specific heat of the metal sample is 2.09899 J/g℃.

5 0
3 years ago
The concentration of a biomolecule inside a rod‑shaped prokaryotic cell is 0.0035 M . Calculate the number of molecules inside t
timama [110]

Answer: This rod-shape prokaryotic cell has 3.740,734725‬ molecules

Explanation:

<u>Step 1 :</u> given data

Molarity of the prokaryotic cell = 0.0035 M

Length of the cell = 4.2 μm = 4.2 * 10^-6 m

diameter of the cell = 1.3 μm = 1.3 * 10^-6 m

<u>Step 2: </u>calculate volume

To calculate volume of a rod, weneef to know the radius.

V = r ² × l

The radius = half of the diameter : r = d/2 ⇒ (1.3 * 10^-6 m)/2 = 0.65 * 10^-6 m

V= (0.65 * 10^-6 m)² * 4.2 * 10^-6 m = 1.7745 * 10 ^-18 L

<u>Step 3:</u> Calculating number of moles

Number of moles = Concentration * Volume

moles = 0.0035 M * 1.7745 * 10 ^-18 L = 6.21075 * 10^-21 moles‬

<u>Step 4:</u> calculating number of molecules

1 mole contains 6.023 * 10 ^-23 molecules

6.21075 * 10^-21 moles contain : 6.21075 * 10^-21 * 6.023 * 10 ^-23 molecules = 3.740,734725‬ molecules

This rod-shape prokaryotic cell has 3.740,734725‬ molecules

4 0
3 years ago
Complete and balance the following redox reaction in basic solution
inn [45]

Answer:

balanced in ACID not BASE

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

Answer

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

Explanation:

Cr2O7^2-(aq) + Hg(l) ----> Hg^2+(aqH) + Cr^3+(aq)

add H^1+ (acid) to capture the O and make 7 water molecules

Cr2O7^2-(aq) + Hg(l) + H^1+ ----> Hg^2+(aqH) + Cr^3+(aq) + 7H2O

Cr goes from +6 to +3 by gaining 3 e

Hg goes from 0 to +2 by losing 2 e

we need 3 Hg for every 2 Cr

so

Cr2O7^2-(aq) +3Hg(l) +14 H^1+ ----> 3Hg^2+ + 2Cr^3+(aq) + 7H2O

2 Cr on the right and left

Net 12 positive charges on the right and the left

3 Hg on the right and left

14 H on the right and left

the equation is balanced

we cannot balance the equation in a basic solution with OH^1-

we have plenty of O in the dichromate ion. we need to convert it to water which take free H^1+ from the acid

8 0
3 years ago
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