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Trava [24]
3 years ago
8

Can anyone please help me

Chemistry
1 answer:
mixas84 [53]3 years ago
4 0
Q1. Chemical, Physical, Physical, Physical
(l am not 100% sure about the 4th answer)

Q2. All of the above 
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Consider the double replacement reaction given below: HgNO3(aq) + KBr(aq) → HgBr (??) + KNO3(??)The state of matter for HgBr wou
Andreas93 [3]

Answer: The state of maater for HgBr is solid.

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.  

The balanced chemical equation is:

HgNO_3(aq)+KBr(aq)\rightarrow HgBr(s)+KNO_3(aq)

7 0
2 years ago
Describe what happens in a condensation reactions
dlinn [17]
A condensation reaction is described to be a reaction wherein two molecules form an even larger product and consequently produces a smaller molecule as a by-product. For example, when two amino acids are combined, a dipeptide bond is formed. As a result, 1 molecule of water is produced as a by-product.
5 0
2 years ago
This stadium can hold 100,000, or 1 x 10^5, people. The number of atoms in a grain of iron is about 1 x 10^18. Would you need 1 
polet [3.4K]
<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

From the question;

1 x 10^5 people can fill 1 stadium

We are given,  1 x 10^18 atoms of iron

We are required to determine the number of stadiums that  1 x 10^18 atoms of iron would occupy.

We are going to assume that a stadium would occupy a number of atoms equivalent to the number of people.

Therefore;

One stadium =  1 x 10^5 atoms

Then, to find the number of stadiums that will be occupied by  1 x 10^18 atoms;

No. of stadiums = Total number of atoms ÷ Atoms in a single stadium

                           =  1 x 10^18 atoms ÷  1 x 10^5 atoms

                          =  1 x 10^13 stadiums

Therefore,  1 x 10^18 atoms of iron would occupy  1 x 10^13 stadiums

7 0
2 years ago
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