Answer:
Yes
Explanation:
Denatured ethanol fuel is a polar solvent, which is soluble in water. A
Polar solvent is a compound with a charge separation in chemical bonds, such as alcohol, most acids, or ammonia. These have affinity with water and will dissolve easily. Denatured fuel ethanol has a flash point of -5 ° F and a vapor density of 1.5, indicating that it is heavier than air.
Consequently, ethanol vapors do not rise, similar to the gasoline vapors they are looking for lower altitudes. The specific gravity of denatured fuel ethanol is 0.79, which indicates that it is lighter than water and has a self-ignition temperature of 709 ° F and a boiling point of 165-175 ° F. Like gasoline, the most denatured fuel, the greatest danger of ethanol as an engine fuel component is its flammability.
It has a wider flammable range than gasoline (LEL is 3% and UEL is 19%).
Answer:
the final volume of the gas is 
= 1311.5 mL
Explanation:
Given that:
a sample gas has an initial volume of 61.5 mL
The workdone = 130.1 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm ; we have
External Pressure 
:
The workdone W = V
The change in volume ΔV= 
ΔV = 
ΔV = 
ΔV = 1.25 L
ΔV = 1250 mL
Recall that the initial volume = 61.5 mL
The change in volume V is 
multiply through by (-), we have:
= 1250 mL + 61.5 mL
= 1311.5 mL
∴ the final volume of the gas is = 1311.5 mL
Jupiter looks as if it has stripes, thanks to the gas that surrounds it :)
Answer: 5.4
Explanation:
P2 = P1V1/V2
P2 = (.60atm x 27L) / 3.0L = 5.4atm
Answer:
Mass = 18.9 g
Explanation:
Given data:
Mass of Al₂O₃ formed = ?
Mass of Al = 10.0 g
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Number of moles of Al:
Number of moles = mass/molar mass
Number of moles = 10.0 g/ 27 g/mol
Number of moles = 0.37 mol
Now we will compare the moles of Al and Al₂O₃.
Al : Al₂O₃
4 : 2
0.37 : 2/4×0.37 = 0.185 mol
Mass of Al₂O₃:
Mass = number of moles × molar mass
Mass = 0.185 mol × 101.9 g/mol
Mass = 18.9 g
