The formula in terms of h is h = 3V/s^2 and the value of h is 5
<h3>How to write the formula in terms of h?</h3>
The equation is given as
V = 1/3s^2h
Divide both sides of the equation by 1/3s^2
So, we have
h = 3V/s^2
The given parameters are
V = 60 and s = 6
So, we have:
h = 3 * 60/6^2
Evaluate
h = 5
Hence, the formula in terms of h is h = 3V/s^2 and the value of h is 5
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Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Answer:
- x^2 -2x +3
- x^2 +2x +3
Step-by-step explanation:
The quotient in each case can be found by any of several means, including synthetic division (possibly the easiest), polynomial long division, or graphing.
1. The graph shows you the quotient is (x-1)^2 +2 = x^2 -2x +3.
2. The graph shows you the quotient is (x+1)^2 +2 = x^2 +2x +3.
25a is true
25b is true
25c is false
25d is false
