Using translation concepts, the equation of g(x) is given as follows:
<h3>What is a translation?</h3>
A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.
For this problem, the parent function is given by:
For a horizontal compression by a factor of 1/5, we have to find f(1/5x), hence:
For a vertical stretch by a factor of 7, we have to multiply by 7, hence:
For a reflection in the y-axis, we have to find g(-x), hence:
For a translation of 10 units left, we have to find g(x + 10), hence:
For a translation of 1 unit down, we have to subtract one, hence:
More can be learned about translation concepts at brainly.com/question/28174785
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Answer:
see below
Step-by-step explanation:
14. We can represent 1 as √1 and 2 as √4 and because 1 < 3 < 4, we know that √3 is in between 1 and 2. However, 3 is closer to 4 than it is to 1 so √3 is about 2.
15. Again, 3 is √9 and 4 is √16. 9 < 10 < 16 so √10 is in between 3 and 4, however, since 10 is closer to 9 as it is to 16, we know that √10 is about 3.
16. -4 = -√16 and -5 = -√25, since 16 < 22 < 25, we know that -√22 is in between -4 and -5 but 22 is closer to 25 so the answer is -5.
17. -10 = -√100 and -11 = -√121 so -√120 is in between -10 and -11. Since 120 is closer to 121, the answer is -11.
Answer:
The missing dimension, radius = 6.00 m
Step-by-step explanation:
We are given the following things:
Height of cylinder, 
= 15 m
Radius of cylinder, 
m (Labelled as 
)
Volume of cylinder, 
Please refer to the image attached for the dimensions of cylinder as given.
We know that the volume of a cylinder can be given as:
Where 
is the radius of cylinder
is the height of cylinder
Putting the values of 
:
Hence, The missing dimension, radius = 6.00 m
Answer:0.75 milligrams will be present in 24 hours
Step-by-step explanation:
Step 1
The formula for radioactive decay can be written as
N(t)=No (1/2)^(t/t 1/2)
where
No= The amount of the radioactive substance at time=0=milligrams
t 1/2= the half-life= 6 hours
t=24 hours
N(t) = the amount at time t
Step 2--- Solving
N(t)=No (1/2)^(t/t 1/2)
=N(t)=12 x ( 1/2) ^ (24/6)
= 12 x (1/2) ^4
= 12 x 0.0625
= 0.75 milligrams
you need another equation to solve them simultaneously since they are two unknown
