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Scorpion4ik [409]
4 years ago
13

Pinion gear-to-flywheel ring gear clearance is being discussed: Technician A says that if there is too much clearance, there wil

l be a high pitch whine while the engine cranks. Technician B says that if there is too little clearance, there will be a high pitch noise after the engine is started. Who is correct?
(A) Technician A
(B) Technician B
(C) Both A and B
(D) Neither A nor B
Engineering
1 answer:
maks197457 [2]4 years ago
4 0

Answer:C both Technician A and B are correct with their analysis.

Explanation: Gear clearances MUST be checked to be sure it is not too little or too much. pinion gear-to-flywheel ring-gear gap must be 1/8 in its relaxed position. If this gap is too small, use shims to move the pinion away from the ring gear. If this gap is too large, remove the shims already in the starter.

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4 0
2 years ago
Solve using Matlab the problems:
Firlakuza [10]

Answer:

Explanation:

% Clears variables and screen

clear; clc

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p = 1;

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   p = p*i;

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7 0
3 years ago
How does the clearance volume affect the efficiency of the Otto cycle?
eduard

Answer:

Explanation:

A smaller clearance volume means a higher compression. A higher compression means better thermal efficiency. However a compression ratio too high might be troublesome, as it can cause accidental ignition of the fuel-air mix. This is the reason why Otto cycle engines have lower compressions that Diesel engines. In a Diesel engine the mix ignites by compression instead of a spark.

7 0
3 years ago
To make an even better electrical junction, what should you do?
docker41 [41]

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A:Solder it.

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Hopefully this helps!

4 0
3 years ago
Suppose that the weights for newborn kittens are normally distributed with a mean of 125 grams and a standard deviation of 15 gr
kherson [118]

(a) If a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

(b) For a kitten to be at 90th percentile, the minimum weight is 146.45 g.

<h3>Weight distribution of the kitten</h3>

In a normal distribution curve;

  • 2 standard deviation (2d) below the mean (M), (M - 2d) is at 2%
  • 1 standard deviation (d) below the mean (M), (M - d) is at 16 %
  • 1 standard deviation (d) above the mean (M), (M + d) is at 84%
  • 2 standard deviation (2d) above the mean (M), (M + 2d) is at 98%

M - 2d = 125 g - 2(15g) = 95 g

M - d = 125 g - 15 g = 110 g

95 g is at 2% and 110 g is at 16%

(16% - 2%) = 14%

(110 - 95) = 15 g

14% / 15g = 0.93%/g

From 95 g to 99 g:

99 g - 95 g  = 4 g

4g x 0.93%/g = 3.72%

99 g will be at:

(2% + 3.72%) = 5.72%

Thus, if a kitten weighs 99 grams at birth, it is at 5.72 percentile of the weight distribution.

<h3>Weight of the kitten in the 90th percentile</h3>

M + d = 125 + 15 = 140 g      (at 84%)

M + 2d = 125 + 2(15) = 155 g   ( at 98%)

155 g - 140 g = 15 g

14% / 15g = 0.93%/g

84% + x(0.93%/g) = 90%

84 + 0.93x = 90

0.93x = 6

x = 6.45 g

weight of a kitten in 90th percentile = 140 g + 6.45 g  = 146.45 g

Thus, for a kitten to be at 90th percentile, the approximate weight is 146.45 g

Learn more about standard deviation here: brainly.com/question/475676

#SPJ1

7 0
2 years ago
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